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c - 如何快速排序用户输入

转载 作者:塔克拉玛干 更新时间:2023-11-03 03:17:29 24 4
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问题很简单,但我搜索得越多,我就越困惑。我应该从我编写的结构代码中快速排序一个变量。但是,我不明白我应该如何快速排序像 em.fName 这样的变量,如果它在循环的每次迭代中都发生了变化。我查找的每个示例似乎都对 int 变量或预定义的字符数组进行排序。有人能指出我从哪里开始的正确方向和/或用 C 语言举个例子吗?谢谢,非常感谢。我有 posted the full code here 因为我不想弄乱帖子。

    typedef struct EmployeeRecord
{
STR21 lName;
STR11 fName;
char fullName[33];
float hrs;
float pay;
float dfr;
float gross;
float ft;
float st;
float ssit;
float net;

} EmployeeRecord;

int main(void)
{
EmployeeRecord em;

do
{
counter++;
em.dfr = em.ft = em.st = em.ssit = em.gross = em.hrs = em.pay = em.net = ovrtHrs = 0; //initalized to 0 and then changed by function if greater than 0
printf("Please enter your FIRST name: ");
scanf("%s",fName);
printf("Please enter your LAST name: ");
scanf("%s",lName);
printf("Enter your payrate: ");
scanf("%f",&em.pay);
printf("Please enter your total hours: ");
scanf("%f",&em.hrs);
printf("Please enter the amount of deferred earnings: ");
scanf("%f",&em.dfr);

strcpy(fullName,lName); // combine last + ", " + first into full
strcat(fullName,", ");
strcat(fullName,fName);

payTotal = payTotal + em.pay;
dfrTotal = dfrTotal + em.dfr;

em.gross = grossModule(&em.hrs,em.pay,&ovrtHrs); // call 3.4
CalculateTaxes(&em.gross,&em.dfr,&em.ft,&em.st,&em.ssit); // call 3.0
em.net = netModule(&em.gross,&em.ft,&em.st,&em.ssit); // cal 3.5

hoursTotal = hoursTotal + em.hrs;
overtimeTotal = overtimeTotal + ovrtHrs; // TOTALS
grossTotal = grossTotal + em.gross;
stateTotal = stateTotal + em.st;
ssiTotal = ssiTotal + em.ssit;
netTotal = netTotal + em.net;
fedTotal = fedTotal + em.ft;

fprintf(myreport,REPORTCOLUMNFORMATS,em.fullName,em.pay,em.hrs,em.gross,em.ft,em.ssit,em.net);
fprintf(myreport,REPORTCOLUMNFORMATS3,ovrtHrs,em.st,em.dfr);


printf("Would you like to continue, y/n? \n");
scanf("%s",&ask);

}while(ask == 'y' || ask == 'Y');

最佳答案

这里有一些提示:

  1. 您只读取一个 EmployeeRecord,然后它被覆盖,如果您想对它们进行排序,则必须将它们全部保存。您可以使用 realloc 来动态更改保留空间的大小或保持简单:

    EmployeeRecord employees[100]; // will fail if more than 100 employees are added
    ...
    // after em is complete:
    employees[counter++] = em; // remove the other counter++
  2. 排序取自 wikibooks.org 并用普通 int 替换指针,使用索引而不是指针数学(更容易理解)并添加您必须填写的比较函数:

    void swap(int a, int b)
    {
    EmployeeRecord tmp = employees[a];
    employees[a] = employees[b];
    employees[b] = tmp;
    }

    int compare(int a, int b)
    {
    // return -1 if employees[a] comes before employees[b]
    // return 1 if employees[a] comes after employees[b]
    // return 0 "if they have the same order"
    // (stable algorithms e.g. mergesort won't change the order of those)
    }

    void quicksort(int begin, int end)
    {
    int ptr;
    int split;
    if (end - begin <= 1)
    return;
    ptr = begin;
    split = begin + 1;
    while (++ptr <= end) {
    if (compare(ptr, split) > 0) { // sorts ascending
    swap(ptr, split);
    ++split;
    }
    }
    swap(begin, split - 1);
    quicksort(begin, split - 1);
    quicksort(split, end);
    }
  3. 在用户决定不再继续后排序并创建报告。

关于c - 如何快速排序用户输入,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31662884/

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