java - SpringBoot 不处理 org.hibernate.exception.ConstraintViolationException

Question

我已经在我的实体类中定义了一个验证电子邮件的模式。在我的验证异常处理程序类中，我添加了 ConstraintViolationException 的处理程序。我的应用程序使用 SpringBoot 1.4.5。

配置文件.java

@Entity
@EntityListeners(AuditingEntityListener.class)
@Table(name = "profile")
public class Profile extends AuditableEntity {

  private static final long serialVersionUID = 8744243251433626827L;

  @Column(name = "email", nullable = true, length = 250)
  @NotNull
  @Pattern(regexp = "^([^ @])+@([^ \\.@]+\\.)+([^ \\.@])+$")
  @Size(max = 250)
  private String email;
....
}

ValidationExceptionHandler.java

@ControllerAdvice
public class ValidationExceptionHandler extends ResponseEntityExceptionHandler {

  private MessageSource messageSource;

  @Autowired
  public ValidationExceptionHandler(MessageSource messageSource) {
    this.messageSource = messageSource;
  }

  @ExceptionHandler(ConstraintViolationException.class)
  public ResponseEntity<Object> handleConstraintViolation(ConstraintViolationException ex,
  WebRequest request) {
    List<String> errors = new ArrayList<String>();
    ....
    }
} 

当我运行代码并传递无效的电子邮件地址时，出现以下异常。 handleConstraintViolation 中的代码永远不会执行。异常中返回的 http 状态是 500，但我想返回 400。知道如何实现吗？

2017-07-12 22:15:07.078 ERROR 55627 --- [nio-9000-exec-2] o.h.c.s.u.c.UserProfileController        : Validation failed for classes [org.xxxx.common.service.user.domain.Profile] during persist time for groups [javax.validation.groups.Default, ]
List of constraint violations:[
ConstraintViolationImpl{interpolatedMessage='must match "^([^ @])+@([^ \.@]+\.)+([^ \.@])+$"', propertyPath=email, rootBeanClass=class org.xxxx.common.service.user.domain.Profile, messageTemplate='{javax.validation.constraints.Pattern.message}'}]

javax.validation.ConstraintViolationException: Validation failed for classes [org.xxxx.common.service.user.domain.Profile] during persist time for groups [javax.validation.groups.Default, ]
List of constraint violations:[
ConstraintViolationImpl{interpolatedMessage='must match "^([^ @])+@([^ \.@]+\.)+([^ \.@])+$"', propertyPath=email, rootBeanClass=class org.xxxx.common.service.user.domain.Profile, messageTemplate='{javax.validation.constraints.Pattern.message}'}]

at  org.hibernate.cfg.beanvalidation.BeanValidationEventListener.validate(BeanValidationEventListener.java:138)

at org.hibernate.cfg.beanvalidation.BeanValidationEventListener.onPreInsert(BeanValidationEventListener.java:78)    

Answer 1

您无法捕获 ConstraintViolationException.class，因为它不会传播到代码的那一层，它会被较低的层捕获、包装并在另一种类型下重新抛出。因此，命中您的 Web 层的异常不是 ConstraintViolationException。

在我的例子中，它是一个 TransactionSystemException。我正在使用来自 Spring 的 @Transactional 注释和 JpaTransactionManager。当事务中出现问题时，EntityManager 抛出回滚异常，由 JpaTransactionManager 将其转换为 TransactionSystemException。

所以你可以这样做:

@ExceptionHandler({ TransactionSystemException.class })
public ResponseEntity<RestResponseErrorMessage> handleConstraintViolation(Exception ex, WebRequest request) {
    Throwable cause = ((TransactionSystemException) ex).getRootCause();
    if (cause instanceof ConstraintViolationException) {
        Set<ConstraintViolation<?>> constraintViolations = ((ConstraintViolationException) cause).getConstraintViolations();
        // do something here
    }
}