c# - BSP地牢生成的简单例子

Question

我本来想关注this algorithm在 C# 中创建一个简单的 roguelike 地牢。但我想我太愚蠢了，因为我的结果总是一团糟。

然后我切换到我自己的算法，该算法产生的结果不是很好，但可以半识别为地牢。

有没有人有任何以 BSP 方式执行此操作的示例，如链接文章中所述？如果它不被一堆游戏细节/库调用所阻碍，那将是最好的，因为(再次)我很愚蠢。

(如果您特别自虐并希望我发布我的代码，我可以，但我认为这对于 SO 问题来说太过分了。)

Answer 1

这还没有链接房间，但它使用描述的算法生成了好的地牢。 (不幸的是，它是用 Java 编写的，但我试图添加一些注释来阐明正在做什么。)

public static class Rectangle {  

    private static int MIN_SIZE = 5;
    private static Random rnd = new Random(); 

    private int top, left, width, height;
    private Rectangle leftChild;
    private Rectangle rightChild;
    private Rectangle dungeon;

    public Rectangle(int top, int left, int height, int width) {
        this.top = top;
        this.left = left;
        this.width = width;
        this.height = height;
    }

    public boolean split() {
        if( leftChild != null ) //if already split, bail out
            return false;
        boolean horizontal = rnd.nextBoolean(); //direction of split
        int max = (horizontal ? height : width ) - MIN_SIZE; //maximum height/width we can split off
        if( max <= MIN_SIZE ) // area too small to split, bail out
            return false;
        int split = rnd.nextInt( max ); // generate split point 
        if( split < MIN_SIZE )  // adjust split point so there's at least MIN_SIZE in both partitions
            split = MIN_SIZE;
        if( horizontal ) { //populate child areas
            leftChild = new Rectangle( top, left, split, width ); 
            rightChild = new Rectangle( top+split, left, height-split, width );
        } else {
            leftChild = new Rectangle( top, left, height, split );
            rightChild = new Rectangle( top, left+split, height, width-split );
        }
        return true; //split successful
    }

    public void generateDungeon() {
        if( leftChild != null ) { //if current are has child areas, propagate the call
            leftChild.generateDungeon();
            rightChild.generateDungeon();
        } else { // if leaf node, create a dungeon within the minimum size constraints
            int dungeonTop = (height - MIN_SIZE <= 0) ? 0 : rnd.nextInt( height - MIN_SIZE);
            int dungeonLeft =  (width - MIN_SIZE <= 0) ? 0 : rnd.nextInt( width - MIN_SIZE);
            int dungeonHeight = Math.max(rnd.nextInt( height - dungeonTop ), MIN_SIZE );;
            int dungeonWidth = Math.max(rnd.nextInt( width - dungeonLeft ), MIN_SIZE );;
            dungeon = new Rectangle( top + dungeonTop, left+dungeonLeft, dungeonHeight, dungeonWidth);
        }
    }

}

下面是一个演示其用法的测试类:

import java.util.ArrayList;
import java.util.Random;


public class GenerateDungeon {

    private static Random rnd = new Random(); 



    public static void main(String[] args) {
        ArrayList<Rectangle> rectangles = new ArrayList<Rectangle>(); // flat rectangle store to help pick a random one
        Rectangle root = new Rectangle( 0, 0, 60, 120 ); //
        rectangles.add( root  ); //populate rectangle store with root area
        while( rectangles.size() < 19 ) { // this will give us 10 leaf areas
            int splitIdx = rnd.nextInt( rectangles.size() ); // choose a random element
            Rectangle toSplit = rectangles.get( splitIdx); 
            if( toSplit.split() ) { //attempt to split
                rectangles.add( toSplit.leftChild );
                rectangles.add( toSplit.rightChild );
            } 

        }
        root.generateDungeon(); //generate dungeons

        printDungeons(rectangles); //this is just to test the output

    }



    private static void printDungeons(ArrayList<Rectangle> rectangles) {
        byte [][] lines = new byte[60][];
        for( int i = 0; i < 60; i++ ) {
            lines[ i ] = new byte[120];
            for( int j = 0; j < 120; j++ )
                lines[ i ][ j ] =  -1;
        }
        byte dungeonCount = -1;
        for( Rectangle r : rectangles ) {
            if( r.dungeon == null )
                continue;
            Rectangle d = r.dungeon;
            dungeonCount++;
            for( int i = 0; i < d.height; i++ ) {
                for( int j = 0; j < d.width; j++ )

                    lines[ d.top + i ][ d.left+ j ] = dungeonCount;
            }
        }
        for( int i = 0; i < 60; i++ ) {
            for( int j = 0; j < 120; j++ ) {
                if( lines[ i ][ j ] == -1 )
                    System.out.print( '.');
                else
                    System.out.print( lines[ i ][ j ] );
            }
            System.out.println();
        }
    }

}