python - Hammerwatch 拼图；用 Python 解决-6ren

python - Hammerwatch 拼图；用 Python 解决

转载作者：塔克拉玛干更新时间：2023-11-03 03:01:47

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所以，我妻子在 Steam 上玩 Hammerwatch。她遇到了一个难题，我决定尝试为其编写解决方案。

拼图的原理如下:
激活一个开关可以打开或关闭该开关，也可以切换其相邻的开关。

这是游戏中拼图的 YouTube 视频:
http://www.youtube.com/watch?v=OM1XD7IZ0cg

我想出了如何让拼图的机制正常工作。我最终意识到我有两种选择可以让计算机解决这个问题:

A)让电脑随机选择开关来解决
……或者……
B) 创建一个算法，让计算机更有效地解决难题。

作为一名新程序员(CodeAcademy 教程学习了一半，LPTHW 学习了一半，目前正在学习 MIT edX 计算机科学 Python 类(class))，我觉得我解决这个问题的能力有点有限。我是来学习的!请帮忙!

请帮忙:

我需要帮助，要么想出一种更好的方法来随机解决这个问题，要么更好地找到一种算法，让计算机系统地解决这个难题。

我唯一能做的就是让计算机存储列表或字典中的拼图状态，通过跳过那些存储的状态来协助程序，指向程序到新的可能的解决方案

当前程序的工作原理:

我打算让用户使用前 9 个 raw_inputs 输入拼图板的当前状态。然后它进入一个循环，随机切换拼图板的开关，直到它们全部打开。

P.S.:当我注册 StackOverflow 帐户并输入此消息时，我的计算机一直在后台运行此程序以寻找解决方案。已经大约一个小时了，仍然没有找到解决方案，它目前正在进行 ~92,000,000 次迭代。我认为它不起作用...

import random

def switcheroo(x):
    """
    switches 'x' to 1 if it's a 0 and vice-versa
    """
    if x == 0:
        x = 1
    else:
        x = 0
    return x

# original input variables
a1 = 0
a2 = 0
a3 = 0
b1 = 0
b2 = 0
b3 = 0
c1 = 0
c2 = 0
c3 = 0


# puzzleboard   
print "\n\n"
print "    1   2   3   "
print "  -------------"
print "a |",a1,"|",a2,"|",a3,"|"
print "  -------------"
print "b |",b1,"|",b2,"|",b3,"|"
print "  -------------"
print "c |",c1,"|",c2,"|",c3,"|"
print "  -------------"
print "\n\n"



print "What's ON/OFF? (type 0 for OFF, 1 for ON)"
a1 = int(raw_input("a1: "))
a2 = int(raw_input("a2: "))
a3 = int(raw_input("a3: "))
b1 = int(raw_input("b1: "))
b2 = int(raw_input("b2: "))
b3 = int(raw_input("b3: "))
c1 = int(raw_input("c1: "))
c2 = int(raw_input("c2: "))
c3 = int(raw_input("c3: "))

# for counting the iterations within the loop
iteration = 0

# to stop loop if all switches are ON
ans = a1 and a2 and a3 and b1 and b2 and b3 and c1 and c2 and c3


while ans == False:
    # randomly generates number, flipping random switches
    counter = random.randint(1,9)
    if counter == 1:
        switch = "a1"
    elif counter == 2:
        switch = "a2"
    elif counter == 3:
        switch = "a3"
    elif counter == 4:
        switch = "b1"
    elif counter == 5:
        switch = "b2"
    elif counter == 6:
        switch = "b3"
    elif counter == 7:
        switch = "c1"
    elif counter == 8:
        switch = "c2"
    elif counter == 9:
        switch = "c9"


    # PUZZLE MECHANICES #
    if switch == "a1":
        a1 = switcheroo(a1)
        a2 = switcheroo(a2)
        b1 = switcheroo(b1)

    if switch == "a2":
        a2 = switcheroo(a2)
        a1 = switcheroo(a1)
        a3 = switcheroo(a3)
        b2 = switcheroo(b2)        

    if switch == "a3":
        a3 = switcheroo(a3)
        a2 = switcheroo(a2)
        b3 = switcheroo(b3)

    if switch == "b1":
        b1 = switcheroo(b1)
        b2 = switcheroo(b2)
        a1 = switcheroo(a1)
        c1 = switcheroo(c1)

    if switch == "b2":
        b2 = switcheroo(b2)
        a2 = switcheroo(a2)
        b1 = switcheroo(b1)
        b3 = switcheroo(b3)
        c2 = switcheroo(c2)

    if switch == "b3":
        b3 = switcheroo(b3)
        b1 = switcheroo(b1)
        b2 = switcheroo(b2)
        c3 = switcheroo(c3)
    # Edit 1
    if switch == "c1":
        c1 = switcheroo(c1)
        c2 = switcheroo(c2)
        b1 = switcheroo(b1)

    if switch == "c2":
        c2 = switcheroo(c2)
        c1 = switcheroo(c1)
        c3 = switcheroo(c3)
        b2 = switcheroo(b2)

    if switch == "c3":
        c3 = switcheroo(c3)
        c2 = switcheroo(c2)
        b3 = switcheroo(b3)
    if switch == "stop":
        break

    # prints puzzle-board state at end of loop iteration
    print "\n\n"
    print "    1   2   3   "
    print "  -------------"
    print "a |",a1,"|",a2,"|",a3,"|"
    print "  -------------"
    print "b |",b1,"|",b2,"|",b3,"|"
    print "  -------------"
    print "c |",c1,"|",c2,"|",c3,"|"
    print "  -------------"
    print "\n\n"

    # prints which # was randomly generated
    print "random #: ", counter

    # tracks loop iteration
    iteration += 1
    print "iteration", iteration



if ans == True:
    print "I figured it out!"