java - Spring Boot 动态查询

Question

我的网络应用程序中有一个过滤器，允许按车辆类型、品牌、燃料、州和城市进行搜索，但所有这些过滤器都是可选的。

我如何使用存储库执行此操作。

Controller 类

@RequestMapping(value = "/vehicle/search", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
public Iterable<Veiculo> findBySearch(@RequestParam Long vehicletype, @RequestParam Long brand, 
        @RequestParam Long model, @RequestParam Long year, 
        @RequestParam Long state, @RequestParam Long city) {
    return veiculoService.findBySearch(vehicletype, brand, model, year, state, city);
}

服务等级

public Iterable<Vehicle> findBySearch(Long vehicletype, Long brand, Long model, Long year, Long state, Long city) {
    if(vehicletype != null){
        //TODO: filter by vehicletype
    }
    if(brand != null){
        //TODO: filter by brand
    }
    if(model != null){
        //TODO: filter by model
    }

    //OTHER FILTERS
    return //TODO: Return my repository with personal query based on filter
}

我还没有实现任何东西，因为我不明白我该如何做这个过滤器。

车辆类别

@Entity
@Table(name = "tb_veiculo")
public class Veiculo {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    private Long id;

    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable(name = "veiculo_opcionais", 
    joinColumns = @JoinColumn(name = "veiculo_id", referencedColumnName = "id"),
    inverseJoinColumns = @JoinColumn(name = "opcional_id", referencedColumnName = "id"))
    private List<Opcional> opcionais;

    @JsonIgnore
    @OneToMany(mappedBy = "veiculo", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    private List<VeiculoImagem> veiculoImagens;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "cambio_id", foreignKey = @ForeignKey(name = "fk_cambio"))
    private Cambio cambio;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "combustivel_id", foreignKey = @ForeignKey(name = "fk_combustivel"))
    private Combustivel combustivel;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "cor_id", foreignKey = @ForeignKey(name = "fk_cor"))
    private Cor cor;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "modelo_id", foreignKey = @ForeignKey(name = "fk_modelo"))
    private Modelo modelo;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "usuario_id", foreignKey = @ForeignKey(name = "fk_usuario"))
    private Usuario usuario;

    @Column(name = "anoFabricacao", nullable = false)
    private int anoFabricacao;

    @Column(name = "anoModelo", nullable = false)
    private int anoModelo;

    @Column(name = "quilometragem", nullable = false)
    private int quilometragem;

    @Column(name = "porta", nullable = false)
    private int porta;

    @Column(name = "valor", nullable = false)
    private double valor;

    //GETTERS AND SETTERS

车辆类型和品牌来自另一张表...我是葡萄牙语，我已将代码翻译成英文...

当它发生时，我需要做什么？

Answer 1

您可以使用 Spring 的规范 API，它是 JPA 标准 API 的包装器，允许您创建更多动态查询。

在你的例子中，我假设你有一个 Vehicle 实体，它有一个字段 brand, year, state, 城市, ... .

如果是这种情况，您可以编写以下规范:

public class VehicleSpecifications {
    public static Specification<Vehicle> withCity(Long city) {
        if (city == null) {
            return null;
        } else {
            // Specification using Java 8 lambdas
            return (root, query, cb) -> cb.equal(root.get("city"), city);
        }
    }

    // TODO: Implement withModel, withVehicleType, withBrand, ...
}

如果你必须做一个连接(例如，如果你想检索 Vehicle.city.id)那么你可以使用:

return (root, query, cb) -> cb.equal(root.join("city").get("id"), city);

现在，在您的存储库中，您必须确保从 JpaSpecificationExecutor 进行扩展，例如:

public interface VehicleRepository extends JpaRepository<Vehicle, Long>, JpaSpecificationExecutor<Vehicle> {

}

通过扩展此接口(interface)，您将可以访问 findAll(Specification spec)允许您执行规范的方法。如果您需要组合多个规范(通常一个过滤器 = 一个规范)，您可以使用 Specifications类:

repository.findAll(where(withCity(city))
    .and(withBrand(brand))
    .and(withModel(model))
    .and(withVehicleType(type))
    .and(withYear(year))
    .and(withState(state)));

在上面的代码示例中，我对 Specifications.where 和 VehicleSpecifications.* 使用了静态导入，以使其看起来更具声明性。

您不必在这里编写 if() 语句，因为我们已经在 VehicleSpecifications.withCity() 中编写了它们。只要您从这些方法返回 null，它们就会被 Spring 忽略。