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java - 如何使用 Gson 序列化 java.nio.file.Path?

转载 作者:塔克拉玛干 更新时间:2023-11-03 02:56:18 27 4
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尝试序列化包含 java.nio.file.PathObject 时出现 java.lang.StackOverflowError

即使我写:

public class PathConverter implements JsonDeserializer<Path>, JsonSerializer<Path> {
@Override
public Path deserialize(JsonElement jsonElement, Type type, JsonDeserializationContext jsonDeserializationContext) throws JsonParseException {
return Paths.get(jsonElement.getAsString());
}

@Override
public JsonElement serialize(Path path, Type type, JsonSerializationContext jsonSerializationContext) {
return new JsonPrimitive(path.toString());
}
}

并应用它:

    String json = new GsonBuilder()
.registerTypeAdapter(Path.class, new PathConverter())
.create()
.toJson(constructorSetup, new TypeToken<ConstructorSetup>() {}.getType());

我仍然无法序列化这个类:

public class ConstructorSetup {

private Path appIconMimmapDirPathOnPc;

}

堆栈跟踪:(完整信息 pastebin)

Exception in thread "main" java.lang.StackOverflowError
at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:375)
at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
...
at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:355)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:117)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
at com.google.gson.Gson.getAdapter(Gson.java:356)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.<init>(ReflectiveTypeAdapterFactory.java:82)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.createBoundField(ReflectiveTypeAdapterFactory.java:81)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:118)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
at com.google.gson.Gson.getAdapter(Gson.java:356)
...
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.<init>(ReflectiveTypeAdapterFactory.java:82)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.createBoundField(ReflectiveTypeAdapterFactory.java:81)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:118)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
at com.google.gson.Gson.getAdapter(Gson.java:356)

有什么解决办法吗?

最佳答案

你的问题是 Path 是一个 interface。假设您使用了 Paths.get("/"),它将在我的 Windows PC 上创建类似 WindowsPath 的实例。现在,您必须告诉 GSON 如何反序列化此类型:

ConstructorSetup setup = new ConstructorSetup();
setup.setAppIconMimmapDirPathOnPc(Paths.get("/"));

// here we get actual class type of our Path object
Class classT = setup.getAppIconMimmapDirPathOnPc().getClass();

Gson gson = new GsonBuilder().registerTypeAdapter(classT, new MyPathConverter())

您可以使用的另一种方法是registerTypeHierarchyAdapter:

.registerTypeHierarchyAdapter(Path.class, new MyPathConverter())

typeHierarchyAdapter 的目的是涵盖您希望对一个类型的所有子类型使用相同表示的情况,这正是您使用 Path 的情况。

关于java - 如何使用 Gson 序列化 java.nio.file.Path?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36964995/

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