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java - 在 Java 中并行执行依赖任务

转载 作者:塔克拉玛干 更新时间:2023-11-03 02:52:58 25 4
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我需要找到一种在 java 中并行执行任务(依赖和独立)的方法。

  1. 任务 A 和任务 C 可以独立运行。
  2. 任务 B 取决于任务 A 的输出。

我检查了 java.util.concurrent Future 和 Fork/Join,但看起来我们无法将依赖项添加到任务。

任何人都可以指出我更正 Java API。

最佳答案

在 Scala 中这很容易做到,我认为你最好使用 Scala。这是我从这里提取的示例 http://danielwestheide.com/ (Scala 新手指南第 16 部分:从这里到哪里去)这个人有一个很棒的博客(我不是那个人)

让我们以一位 barrista 煮咖啡为例。要做的任务是:

  1. 研磨所需的咖啡 bean (无前置任务)
  2. 加热一些水(没有之前的任务)
  3. 使用咖啡粉和热水冲泡浓缩咖啡(取决于 1 和 2)
  4. 打一些牛奶(没有之前的任务)
  5. 混合奶泡和浓缩咖啡(取决于 3,4)

或者作为一棵树:

Grind   _
Coffe \
\
Heat ___\_Brew____
Water \_____Combine
/
Foam ____________/
Milk

在使用并发 api 的 java 中,这将是:

import java.util.concurrent.Callable;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.FutureTask;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;

public class Barrista {

static class HeatWater implements Callable<String> {
@Override
public String call() throws Exception {
System.out.println("Heating Water");
Thread.sleep(1000);
return "hot water";
}
}

static class GrindBeans implements Callable<String> {
@Override
public String call() throws Exception {
System.out.println("Grinding Beans");
Thread.sleep(2000);
return "grinded beans";
}
}

static class Brew implements Callable<String> {

final Future<String> grindedBeans;
final Future<String> hotWater;

public Brew(Future<String> grindedBeans, Future<String> hotWater) {
this.grindedBeans = grindedBeans;
this.hotWater = hotWater;
}

@Override
public String call() throws Exception
{
System.out.println("brewing coffee with " + grindedBeans.get()
+ " and " + hotWater.get());
Thread.sleep(1000);
return "brewed coffee";
}
}

static class FrothMilk implements Callable<String> {

@Override
public String call() throws Exception {
Thread.sleep(1000);
return "some milk";
}
}

static class Combine implements Callable<String> {

public Combine(Future<String> frothedMilk, Future<String> brewedCoffee) {
super();
this.frothedMilk = frothedMilk;
this.brewedCoffee = brewedCoffee;
}

final Future<String> frothedMilk;
final Future<String> brewedCoffee;

@Override
public String call() throws Exception {
Thread.sleep(1000);
System.out.println("Combining " + frothedMilk.get() + " "
+ brewedCoffee.get());
return "Final Coffee";
}

}

public static void main(String[] args) {

ExecutorService executor = Executors.newFixedThreadPool(2);

FutureTask<String> heatWaterFuture = new FutureTask<String>(new HeatWater());
FutureTask<String> grindBeans = new FutureTask<String>(new GrindBeans());
FutureTask<String> brewCoffee = new FutureTask<String>(new Brew(grindBeans, heatWaterFuture));
FutureTask<String> frothMilk = new FutureTask<String>(new FrothMilk());
FutureTask<String> combineCoffee = new FutureTask<String>(new Combine(frothMilk, brewCoffee));

executor.execute(heatWaterFuture);
executor.execute(grindBeans);
executor.execute(brewCoffee);
executor.execute(frothMilk);
executor.execute(combineCoffee);


try {

/**
* Warning this code is blocking !!!!!!!
*/
System.out.println(combineCoffee.get(20, TimeUnit.SECONDS));
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
} catch (TimeoutException e) {
System.out.println("20 SECONDS FOR A COFFEE !!!! I am !@#! leaving!!");
e.printStackTrace();
} finally{
executor.shutdown();
}
}
}

请确保您添加了超时,以确保您的代码不会永远等待某些事情完成,这是通过使用 Future.get(long, TimeUnit) 然后相应地处理失败来完成的。

然而,它在 scala 中要好得多,就像在博客上一样:准备咖啡的代码如下所示:

def prepareCappuccino(): Try[Cappuccino] = for {
ground <- Try(grind("arabica beans"))
water <- Try(heatWater(Water(25)))
espresso <- Try(brew(ground, water))
foam <- Try(frothMilk("milk"))
} yield combine(espresso, foam)

所有方法都返回一个 future (类型化的 future ),例如 grind 会是这样的:

def grind(beans: CoffeeBeans): Future[GroundCoffee] = Future {
// grinding function contents
}

有关所有实现,请查看博客,但仅此而已。您也可以轻松集成 Scala 和 Java。我真的建议在 Scala 而不是 Java 中做这种事情。 Scala 需要更少的代码,更简洁和事件驱动。

关于java - 在 Java 中并行执行依赖任务,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10855045/

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