linux - 在 linux 中过滤文本输出

Question

我以这种格式从 Junos Switches 获得输出:

Physical interface: ge-0/0/7, Enabled, Physical link is Up
Queue counters:    Queued packets  Transmitted packets   Dropped packets
  0 N4M-Q1                   0          42210774942              1163342

我只需要在一行中包含接口(interface)名称和丢弃的数据包值，如下所示:

ge-0/0/7 - 1163342

我尝试了 sed 和 awk 的多种不同组合。我试图合并 3 行以仅获取我需要的列，但它没有用。这就是我尝试合并行的方式:

cat file.txt.out | awk '{getline b; getline c;printf("%s %s %s\n",$0,b,c)}'

但似乎生成的行太长，所以我无法获得所需的内容。请帮忙

输出看起来像这样(但更长):

Physical interface: ge-0/0/0, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0              4582206                    0
Physical interface: ge-0/0/1, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          14419826529               112564
Physical interface: ge-0/0/2, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          67593521901              1675707
Physical interface: ge-0/0/3, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          44283738671               977315
Physical interface: ge-0/0/4, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          98998665742              5065245
Physical interface: ge-0/0/5, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          56932179711              1446413
Physical interface: ge-0/0/6, Enabled, Physical link is Up
  Queue counters:       Queued packets  Transmitted packets      Dropped packets
    0 N4M-Q1                         0          34955222648               578513

Answer 1

仅凭一 block 样本输入很难猜测，但这可能就是您想要的:

$ awk -v RS= '{print $3, $NF}' file
ge-0/0/7, 1163342

如果没有，请发布您的输入文件的几个 block 而不是一个，这样我们可以更好地了解您要解析的内容。

鉴于您新发布的样本输入，这就是您所需要的:

$ awk '(NR%3)==1{p=$3} (NR%3)==0{print p, $NF}' file
ge-0/0/0, 0
ge-0/0/1, 112564
ge-0/0/2, 1675707
ge-0/0/3, 977315
ge-0/0/4, 5065245
ge-0/0/5, 1446413
ge-0/0/6, 578513