linux - 如何在以 开头的行后添加字符串 “”，但不添加连续的两行？

Question

考虑这个示例文件:

01
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters.
02
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters
Alphabetic characters,
03
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters,

我只想在一行文本中添加字符串。

01
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters.</font>
02
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters
Alphabetic characters,</font>
03
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters,</font>

我不清楚如何排除第一行。有什么建议吗？

Answer 1

这就是我认为你真正想要做的:

$ cat file
01
00:00:00,000 --> 00:00:00,000
Alphabetic characters.
02
00:00:00,000 --> 00:00:00,000
Alphabetic characters
Alphabetic characters,
03
00:00:00,000 --> 00:00:00,000
Alphabetic characters,

$ cat tst.awk
/^[[:alpha:]]/ { buf = (buf ? buf RS : "") $0; next }
buf { printf "<fc=ff00>%s</font>\n", buf; buf="" }
{ print }
END { if (buf) printf "<fc=ff00>%s</font>\n", buf }

$ awk -f tst.awk file
01
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters.</font>
02
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters
Alphabetic characters,</font>
03
00:00:00,000 --> 00:00:00,000
<fc=ff00>Alphabetic characters,</font>