linux - Bash - 编辑代码行

Question

这个问题与Bash - Compare 2 lists of files with their md5 check sums有关

我的问题是如何编辑以下代码以显示文件的完整路径而不是仅显示文件名:

awk -F"/" 'FNR==NR{filearray[$1]=$NF; next }!($1 in filearray){printf "%s has a different md5sum\n",$NF}' file1 file2

和

awk -F"/" 'FNR==NR{filelist[$NF]=$NF; next;}!($NF in filelist){printf "%s is an extra file",$NF}' file1 file2

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感谢大家的时间和帮助!

Answer 1

使用 GNU Awk 字符串操作 split-function , 以拆分匹配行，在本例中为 $0 并将其作为单个元素存储在 array 中。

 awk -F"/" 'FNR==NR{filearray[$1]=$NF; next }!($1 in filearray){split($0,array," ");printf "%s has a different md5sum or do not exist in the vanilla core files\n",array[2]}' file2 file1
/home/user/vanila/file-4.php has a different md5sum or do not exist in the vanilla core files

和文件

 awk -F"/" 'FNR==NR{filelist[$NF]=$NF; next;}!($NF in filelist){split($0,array," "); printf "%s is an extra file\n",array[2]}' file1 file2
/home/user/file-1.1.php is an extra file