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c++ - 错误 : Invalid use of incomplete type struct Subject; error: forward declaration of struct Subject

转载 作者:塔克拉玛干 更新时间:2023-11-03 02:04:45 29 4
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我继承自模板类。当我进入教师类(class)时,我想进入学科类(class),反之亦然。我收到错误 Invalid use of incomplete type struct Subect;

void addSubject(Subject *s) {
this->addReference(s);
s->addReference(this); when I comment this line the it compiles without errors, but I cannot insert into Subject

}

我的全部代码在下面

#include <iostream>
#include <stdlib.h>
#include <vector>

using namespace std;
class Subject;


template <class T>
class abstractReference {


vector<T*> list;
public:
string code;
void addReference( T*);
void delReference( T*);
bool hasReference( T*);
T * getReference(int );
};

template <class T>
void abstractReference<T>::addReference(T* ref) {
list.push_back(ref);
//ref->addReference(this);
}

template <class T>
void abstractReference<T>::delReference(T* ref) {
int i;
for (i=0; i<list.size(); i++) {
if (list[i]== ref) list.erase(i);
}

}

template <class T>
bool abstractReference<T>::hasReference( T* ref) {
if (list.size() == 0) return false;
int i;
for (i=0; i<list.size(); i++) {
if (list[i] == ref) return true;
}
return false;
}

template <class T>
T* abstractReference<T>::getReference(int i) {
if (i < 0 || i > list.size()) return NULL;
return list[i];
}

class Teacher : public abstractReference<Subject> {

string fname;
string lname;
float sal;
public:
Teacher(string c, string fn, string ln, float s): fname(fn), lname(ln), sal(s) {
}
Teacher() {sal =0; fname=""; lname="";}
void setInfo(string c, string fn, string ln, float s=0.00) {
code=c;
fname = fn;
lname = ln;
sal = s;
}

string getName() {
return fname + " " + lname;
}

float getSal() {
return sal;
}

void addSubject(Subject *s) {
this->addReference(s);
s->addReference(this);

}

void delSubject(Subject *s) {

}

};

class Subject : public abstractReference<Teacher> {
string title;
public:
Subject(string c=NULL, string t=NULL) {
title = t;

}
string getTitle() {
return title;
}
};

main() {
Teacher *t;
t = new Teacher("J109", "Dexter", "McConnell",15000);
Subject *s, *s1, *s2;
s= new Subject("E001", "English");
s1= new Subject("M001", "Maths");
s2= new Subject("s001", "Science");

t->addSubject(s);
t->addSubject(s1);

cout << "Has Reference " << t->hasReference(s2) << endl;
cout << "Done..." << endl;
cout << t->getReference(1)->getTitle() << endl;
}

最佳答案

问题是编译器不理解类型Subject,你可能前向声明它或者忘记包含定义它的头文件。
结果是,对于编译器来说,Subject 是一个不完整类型,它无法执行任何需要了解 Subject 布局的操作,调用它的成员函数就是这样一个例子。

解决方法是:

您应该在源 cpp 文件中包含定义 Subject 的头文件,您在其中定义了以下内容:

void addSubject(Subject *s)

如果您没有多个文件,请确保类 Subject 已定义之前 您已定义函数 addSubject().

关于c++ - 错误 : Invalid use of incomplete type struct Subject; error: forward declaration of struct Subject,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10275436/

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