Linux脚本显示不必要的文件

Question

我写了下面的脚本，当我运行它时它显示了一些不必要的文件。我只想执行命令并只接收警报。脚本如下

 df -h | nawk '/backup/ {print $5 " "  $6}' | while read line;
  do
        usep=$(echo  $line | nawk  '{printf "%d", $1}' )    
        partition=$(echo $line | nawk '{print $2}')
        if (( $usep >= 90)); then
                 echo "$partition ($usep%)" | mailx -s "172.27.68.101" 0234343456@alert.abc.lk;
                echo  "$partition ($usep%)" | mailx -s "172.27.68.101" amalw@abc.lk;
        echo  "$partition ($usep%)" | mailx -s "172.27.68.101" amalw@abc.lk;
        fi
  done

下图显示输出问题

如何在不打开此类目录的情况下向此脚本添加多个收件人？

Answer 1

要将多行 bash 代码粘贴到终端，请在行周围添加括号，否则每行在粘贴后都会作为单独的命令运行:

(df -h | nawk '/backup/ {print $5 " "  $6}' | while read line; do
    usep=$(echo  "$line" | nawk  '{printf "%d", $1}')
    partition=$(echo $line | nawk '{print $2}')
    if(("$usep" >= 90)) ; then echo "$partition ($usep%)" | mailx -s "172.27.68.101" 0234343456@alert.abc.lk;
        echo  "$partition ($usep%)" | mailx -s "172.27.68.101" amalw@abc.lk;
        echo  "$partition ($usep%)" | mailx -s "172.27.68.101" amalw@abc.lk;
    fi
done)