c++ - 简单的C++类型转换程序

Question

我正在学习 C++，正在研究安全和不安全转换的主题。这是我的代码:

#include <iostream>

using namespace std;
int main()
{
    double d = 0;
    while( cin >> d )
    {
           int i = d; // try to squeez in a double into an int
           char c = i; // try to squeez in an int into a char
           int i2 = c; // try to get the integer value of the char

           cout << "d == " << d << "\n"
                << "i == " << i << "\n"
                << "c == " << c << "\n"
                << "i2 == " << i2 << "\n";
    }
    return 0;
}

当我输入 3 时，我得到以下信息:

d == 3
i == 3
c == a heart shape
i2 == 3

为什么 c 会打印出这样的 hear 形状:link

Answer 1

因为心字是PC版ASCII表中值为3的符号。这是一个 list :http://www.ascii-codes.com/ .假设您的程序在该环境中运行，您可能会发现其他很好的代码。