c++ - QT Get请求解析JSON

Question

我正在尝试制作 GET request为了验证用户。这是我的代码:

void MainWindow::on_loginButton_clicked()
{
    QString email = "test";
    QString password = "test";

    nam = new QNetworkAccessManager(this);
    QObject::connect(nam, SIGNAL(finished(QNetworkReply*)),
             this, SLOT(serviceRequestFinished(QNetworkReply*)));

    QUrl url("http://url.com/api.php?action=authenticate_user&email=" + email + "&password" + password);
    QNetworkReply* reply = nam->get(QNetworkRequest(url));
}

void MainWindow::serviceRequestFinished(QNetworkReply* reply)
{
    if(reply->error() == QNetworkReply::NoError) {

        QStringList propertyNames;
        QStringList propertyKeys;

        QString strReply = (QString)reply->readAll();

        qDebug() << strReply;

        QJsonDocument jsonResponse = QJsonDocument::fromJson(strReply.toUtf8());

        QJsonObject jsonObject = jsonResponse.object();

        QJsonArray jsonArray = jsonObject["status"].toArray();

        qDebug() << jsonObject["status"].toString();

        foreach (const QJsonValue & value, jsonArray)
        {
            QJsonObject obj = value.toObject();
            qDebug() << value.toString();
        }

    } else {
        qDebug() << "ERROR";
    }

    delete reply;
}

但出于某种原因qDebug() << strReply;只是输出:

""Missing argument"" 

Answer 1

服务器告诉您您的请求缺少参数。详细查看请求并仔细检查。

QUrl url("http://url.com/api.php?action=authenticate_user&email=" + email + "&password" + password);

在我看来，URL 是错误的，它不应该在那里说 "&password="+ ... 吗？