c++ - 如何在 ODBC native 客户端中获取 SQL Server 日期时间字段

Question

我有 SQL Server 表:

CREATE TABLE [dbo].[Table1](
    [rec_id] [int] IDENTITY(1,1) NOT NULL,
    [id] [int] NOT NULL,
    [date] [datetime] NOT NULL,
    [ps] [varchar](200) NULL
) ON [PRIMARY]

我通过代码获取数据:

status = SQLExecDirect(statement, (SQLWCHAR*)TEXT("SELECT * FROM [DBNAME].[dbo].[Table1]"), SQL_NTS);
cout << "SQLExecDirect returned " << status << "\r\n";
    if (status == SQL_SUCCESS_WITH_INFO || status == SQL_SUCCESS)
    {
        int rec_id;
        int id;
        char date[64];
        char ps[201] = { 0 };
        while (SQLFetch(statement) == SQL_SUCCESS)
        {
            SQLGetData(statement, 1, SQL_C_ULONG, &rec_id, 0, NULL);
            SQLGetData(statement, 2, SQL_C_ULONG, &id, 0, NULL);
            SQLGetData(statement, 3, SQL_C_CHAR, date, 64, NULL);
            SQLGetData(statement, 4, SQL_C_CHAR, ps, 201, &len);
            cout << rec_id << " " << id << " " << date << " " << ps << " " << len << endl;
        }
    }
    cout << "Connected;";
    cin.get();
    SQLDisconnect(connectHandle);

但我在输出中得到 date 字段作为 char 数组:2014-01-01 00:00:00.000例如，如何以 FILETIME 格式或其他更方便的 C++ 数据类型获取此字段？谢谢。

Answer 1

对于日期类型，您应该使用 SQL_C_DATE 或 SQL_C_TIMESTAMP。示例:

   TIMESTAMP_STRUCT ts;
   SQLLEN           len;
   SQLGetData(hstmt, 3, SQL_C_TIMESTAMP, &ts, sizeof(ts), &len);
   printf("Date: %d-%d-%d %d:%d:%d.%d (%ld)\n",
           ts.year, ts.month,ts.day, ts.hour, ts.minute, ts.second, ts.fraction, len);

希望这对您有所帮助。