c++ - 在单独的插槽中删除发件人

Question

我有一个发出 3 种不同信号的对象，我想传输这些信号并删除它们的发送者。该对象位于另一个对象中，该对象将充当这些信号的发射器。

通常我会这样:

void SomeClass::someSideFunction() {
    Request* request = _StorageProvider.insert("somedata");

    connect(request, SIGNAL(succeded()),        this, SLOT(handleSucceded()));
    connect(request, SIGNAL(failed()),          this, SLOT(handleFailed()));
    connect(request, SIGNAL(alreadyExists()),   this, SLOT(handleAlreadyExists()));
}

void SomeClass::handleSucceded() {
    Request* request = qobject_cast<Request*>(sender());
    if(request != NULL) request ->deleteLater();
    emit succeded();
}

void SomeClass::handleFailed() {
    Request* request = qobject_cast<Request*>(sender());
    if(request != NULL) request ->deleteLater();
    emit failed();
}

void SomeClass::handleAlreadyExists() {
    Request* request = qobject_cast<Request*>(sender());
    if(request != NULL) request ->deleteLater();
    emit alreadyExists();
}

有更好的方法吗？即使“请求”是 storageProvider 的子项，我也有很多请求可以等待删除它们，直到父项死亡。

我在想这样的解决方案:

connect(request, SIGNAL(succeded()),        this, SIGNAL(succeded()));
connect(request, SIGNAL(failed()),          this, SIGNAL(failed()));
connect(request, SIGNAL(alreadyExists()),   this, SIGNAL(alreadyExists()));
connect(request, SIGNAL(succeded()),        this, SLOT(memoryHnadler()));
connect(request, SIGNAL(failed()),          this, SLOT(memoryHnadler()));
connect(request, SIGNAL(alreadyExists()),   this, SLOT(memoryHnadler()));

内存处理程序将删除发件人(如果存在)的位置。这种方法的缺点是什么，什么可能更好？

请注意，对象在完成时只会发出这些信号之一!

Answer 1

一个选项是让请求使用 QObject::deleteLater() 安排它自己的删除。像这样:

void Request::emitSucceeded() {
    emit succeeded();
    deleteLater();
}

void Request::emitFailed(int errorCode, const QString& errorString ) {
    m_errorCode = errorCode;
    m_errorString = errorString;
    emit failed();
    deleteLater();
}

例如，KDELib 的异步操作基类，KJob , 正在使用此模式(除非通过 setAutoDelete(false) 明确禁用)。