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c++ - 没有匹配的成员函数来调用 child.value

转载 作者:塔克拉玛干 更新时间:2023-11-03 01:44:14 24 4
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当我尝试编译下面的代码时出现错误:

src/main.cpp:51:48: error: no matching member function for call to 'child_value'
std::cout << "which has value" << eb.second.child_value(kv.second);
~~~~~~~~~~^~~~~~~~~~~

我不明白的是我能够在上面的循环中使用它。我只能假设它希望我使用 kv.second.child_value(kv.second); 代替。但是我希望它在 for (auto& eb: mapb) {.

返回的 xml 上运行这段代码。
#include "pugi/pugixml.hpp"

#include <iostream>
#include <string>
#include <map>

int main()
{

const std::map<std::string, std::string> tagMap {
{"description", "content"}, {"url", "web_address"}
};

pugi::xml_document doca, docb;
std::map<std::string, pugi::xml_node> mapa, mapb;

if (!doca.load_file("a.xml") || !docb.load_file("b.xml")) {
std::cout << "Can't find input files";
return 1;
}

for (auto& node: doca.child("data").children("entry")) {
const char* id = node.child_value("id");
mapa[id] = node;
}

for (auto& node: docb.child("data").children("entry")) {
const char* idcs = node.child_value("id");
if (!mapa.erase(idcs)) {
mapb[idcs] = node;
}
}

// For removed
for (auto& ea: mapa) {
std::cout << "Removed:" << std::endl;
ea.second.print(std::cout);
}

// For added nodes
for (auto& eb: mapb) {
// Loop through tag map
for (auto& kv : tagMap) {
// Try to find the tag name named in second map value
// and associate it to the type of information in first map value
std::cout << "Found" << kv.first;
std::cout << "which has value" << eb.second.child_value(kv.second);
}
}

}

如果有人能解释我做错了什么,我将不胜感激。

最佳答案

根据两个重载发现here

// Get child value of current node; that is, value of the first child node of type PCDATA/CDATA
const char_t* child_value() const;

// Get child value of child with specified name. Equivalent to child(name).child_value().
const char_t* child_value(const char_t* name) const;

您需要传递一个指向字符串(或字符串文字)的指针。

std::cout << "which has value" << eb.second.child_value(kv.second.c_str());
^^^^^^^^^^^^^^^^^

关于c++ - 没有匹配的成员函数来调用 child.value,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29735239/

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