c - 意外标记附近的语法错误 '('

Question

作为初学者，我正在尝试编写一个简单的 c 程序来学习和执行“写入”功能。

我正在尝试执行一个简单的 C 程序 simple_write.c

#include <unistd.h>
#include <stdlib.h>
int main()
{
    if ((write(1, “Here is some data\n”, 18)) != 18)
         write(2, “A write error has occurred on file descriptor 1\n”,46);
    exit(0);
}

我也执行chmod +x simple_write.c

但是当我执行 ./simple_write.c 时，它给我 syntax error near unexpected token '('

无法弄清楚为什么会这样？？

P.S:预期的输出是:-

$ ./simple_write
Here is some data
$

Answer 1

你做到了

$ chmod +x simple_write.c
$ ./simple_write.c

当你应该做的时候

$ cc simple_write.c -o simple_write$ chmod +x simple_write                 # On second thought, you probably don’t need this.$ ./simple_write

In words: compile the program to create an executable simple_write(without .c) file, and then run that. What you did was attempt to execute your C source code fileas a shell script.

Notes:

• The simple_write file will be a binary file. Do not look at it with tools meant for text files(e.g., cat, less, or text editors such as gedit).

• cc is the historical name for the C compiler. If you get cc: not found (or something equivalent),try the command again with gcc (GNU C compiler). If that doesn’t work,

  • If you’re on a shared system (e.g., school or library),ask a system administrator how to compile a C program.
  • If you’re on your personal computer (i.e., you’re the administrator),you will need to install the compiler yourself (or get a friend to do it). There’s lots of guidance written about this; just search for it.

• When you get to writing more complicated programs,you are going to want to use

  make simple_write
  

  它的优点是

  • 能够协调多步骤构建，这是复杂程序的典型特征，并且
  • 它知道在该系统上编译程序的标准方法(例如，它可能会“知道”是使用 cc 还是 gcc)。

  事实上，你现在应该可以使用上面的命令了。这可能会(也可能不会)简化您的生活。

---

附言既然这个问题在 Stack Overflow 上，我可以谈论它的编程方面。在我看来它应该编译，但是

• 第一个 write 行的括号比它需要的多。

  if (write(1, "Here is some data\n", 18) != 18)
  

  应该可以。

• 在第二行 write 中，我计算字符串的长度为 48 个字符，而不是 46 个。

• 顺便问一下，你知道如何让第一个write失败吗，那么第二个会执行吗？尝试

  ./simple_write >&-