c++ - 从 'size_t' 到 'rapidjson::SizeType' 的转换

Question

我有这个 C++ 示例代码:

void test()
{
    rapidjson::Document doc;
    doc.SetObject();

    const std::string source = "The quick brown fox jumps over the lazy dog";   
    rapidjson::Value source_val;
    source_val.SetString( source.c_str(), source.length(), doc.GetAllocator() );        
}

在编译时，在 x64 平台上，我收到此警告:

warning C4267: 'argument': conversion from size_t to rapidjson::SizeType, possible loss of data

如何正确地将字符串的长度 (size_t) 转换为 rapidjson SizeType？

Answer 1

Per the documentation :

RapidJSON uses 32-bit array/string indices even on 64-bit platforms, instead of using size_t. Users may override the SizeType by defining RAPIDJSON_NO_SIZETYPEDEFINE.