c++ - 检查单选按钮状态 winapi

Question

我使用 mingw32 编译器。我创建了两个单选按钮:

radio1 = CreateWindowExW(WS_EX_TRANSPARENT  , L"BUTTON", L"RadioButton1",
   WS_CHILD | WS_VISIBLE | BS_AUTORADIOBUTTON  ,
   0, 0, 0, 0,
   hwnd, (HMENU)ID_RADIOBTN1,
   GetModuleHandle(NULL), 0);
SendMessage(radioBtnDaily, WM_SETFONT, (WPARAM) font, TRUE);

radio2 = CreateWindowExW(WS_EX_TRANSPARENT  , L"BUTTON", L"RadioButton2",
   WS_CHILD | WS_VISIBLE | BS_AUTORADIOBUTTON  ,
   0, 0, 0, 0,
   hwnd, (HMENU)ID_RADIOBTN2,
   GetModuleHandle(NULL), 0);

SendMessage(radio1, BM_SETCHECK , (WPARAM) font, TRUE);
SendMessage(radio2,  WM_SETFONT, (WPARAM) font, TRUE);

然后我处理检查状态，像这样:

case WM_COMMAND:
    switch(LOWORD(wParam))
    {   
        case ID_RADIOBTN1:
        {
            MessageBoxW( NULL, "radio1 is checked", L"radio", MB_OK | MB_ICONERROR );
        }
        break;

        case ID_RADIOBTN2:
        {
        MessageBoxW( NULL, "radio2 is checked", L"radio", MB_OK | MB_ICONERROR );
        }
        break;
        ....

但是当我点击单选按钮时它总是运行所以它不检查状态。如何在不使用点击事件的情况下查看状态？

Answer 1

使用IsDlgButtonChecked :

if(IsDlgButtonChecked(hwnd, ID_RADIOBTN1))
    MessageBox(NULL, "radio1 is checked")
else
    MessageBox(NULL, "radio1 is not checked")