linux - 运行非常简单的 shell 脚本时出现语法错误

Question

我在运行关于剪刀石头布的小脚本时遇到了这个错误。这是我的代码，它在第二个 elif 语句上失败了，你能找出原因吗？？

function compare () {
    if [ "$userChoice" == "$computerChoice" ]
       then echo "Empate!"
    elif [ "$userChoice" == "piedra" ]
        if [ "$computerChoice" == "tijeras" ]
            then echo "La piedra gana"
        else
            echo "El papel gana"
        fi
    elif [ "$userChoice" == "papel" ]
        if [ "$computerChoice" == "piedra" ]
            then echo "El papel gana"
        else
            echo "Las tijeras ganan"
        fi
    fi
}
compare $userChoice $computerChoice

错误信息是:

myscript: line 10: syntax error near unexpected token `elif'
myscript: line 10: `    elif [ "$userChoice" == "papel" ]'

Answer 1

您忘记了几个“then”语句。永远记住的好方法是将“then”语句添加到与“if”相同的行。示例如下。

function compare () {
if [ "$userChoice" == "$computerChoice" ] ; then
  echo "Empate!"
elif [ "$userChoice" == "piedra" ] ; then
  if [ "$computerChoice" == "tijeras" ] ; then
     echo "La piedra gana"
  else
     echo "El papel gana"
  fi
elif [ "$userChoice" == "papel" ] ; then
  if [ "$computerChoice" == "piedra" ] ; then
     echo "El papel gana"
  else
      echo "Las tijeras ganan"
  fi
fi
}
compare $userChoice $computerChoice