linux - Grep 多个乱序的东西

Question

我目前正致力于在 bash 中创建数据库。我想添加一个“和”功能。这个函数将搜索两个东西，并且只返回匹配两个搜索的东西。我将如何实现？

这是我的代码:

#!/bin/bash

clear

#return all
function all {
    cat people.dat
}
#return some
function search {
    grep -i "$SEARCH" people.dat || echo "search returned nothing"
}
#or search
function or {
    egrep -i "$search1|$search2" people.dat
}
#and search
function and {
    if [[ $(grep -i "$search1") = $(grep -i "$search2") ]]; then
        echo yes
        #that is temporary I want to see if it worked
    fi
}
#return null
function null {
    return
}

while [ true ]
do
    #get the search
    read SEARCH

    #search
    if [[ $SEARCH == *" OR "* ]]; then
        search1=${SEARCH%" OR "*}
        search2=${SEARCH##*" OR "}
        or
    elif [[ $SEARCH == *" AND "* ]]; then
        search1=${SEARCH%" AND "*}
        search2=${SEARCH##*" AND "}
        and
    elif [ "$SEARCH" = "all" }; then
        all
    elif [ "$SEARCH" = "exit" ]; then
        exit
    elif [ "$SEARCH" = "" ]; then
        null
    else
        search
    fi
done

Answer 1

通过管道将第一个 grep 的输出作为第二个 grep 的输入。只有同时包含 $search1 和 $search2 的行才会被返回。

function and {
    if [[ $(grep -i "$search1" people.dat | grep -i "$search2") ]]; then
        echo yes
    fi
}