将以太网地址转换为可读形式？

Question

struct ethernet_header
{
    u_char ether_dhost[ ETHER_ADDR_LEN];

    u_char ether_shost[ETHER_ADDR_LEN];

    u_short ether_type;
};

for(i = 0;i <6; i++)
  printf("dest ether:%x",ethernet->ether_dhost);

如何以正确可读的形式打印以太网地址，每个字节后都有空格？我得到的 o/p 是十六进制的。这里 Ethernet 是指向结构 ethernet_header 的指针。

Answer 1

怎么样:

printf("%02x:%02x:%02x:%02x:%02x:%02x",
    (unsigned)ethernet->ether_dhost[0],
    (unsigned)ethernet->ether_dhost[1],
    (unsigned)ethernet->ether_dhost[2],
    (unsigned)ethernet->ether_dhost[3],
    (unsigned)ethernet->ether_dhost[4],
    (unsigned)ethernet->ether_dhost[5]);