c++ - 如何在大数字中插入空格以使其更具可读性？

Question

我想到了这个，因为 stackoverflow 上提供的其他示例是用 C# 编写的

string number_fmt(ulong n)
{
    // cout << "(" << n << ")" << endl;
    char s[128];
    sprintf(s, "%lu", n);
    string r(s);
    reverse(r.begin(), r.end());
    int space_inserted = 0;
    size_t how_many_spaces = r.length() / 3;

    if(r.length() % 3 != 0)
        how_many_spaces += 1;

    for(int i = 1; i < how_many_spaces; ++i)
    {
        r.insert(3 * i + space_inserted, " ");
        space_inserted += 1;
    }
    reverse(r.begin(), r.end());

    return r;
}

你知道更好的解决方案吗？

Answer 1

我不知道“更好”，但这个版本使用 std::locale 等。

#include <iostream>
#include <locale>
#include <sstream>

template<class Char>
class MyFacet : public std::numpunct<Char> {
public:
  std::string do_grouping() const { return "\3"; }
  Char do_thousands_sep() const { return ' '; }
};

std::string number_fmt(unsigned long n)
{
  std::ostringstream oss;
  oss.imbue(std::locale(oss.getloc(), new MyFacet<char>));
  oss << n;
  return oss.str();
}

int main() {
  std::cout << number_fmt(123456789) << "\n";
}

---

编辑:当然，如果您的最终目标是在 ostream 上打印值，您可以完全跳过将它们存储在 string 中。< p>

#include <iostream>
#include <locale>
#include <sstream>
#include <cwchar>

template <class Char>
class MyFacet : public std::numpunct<Char> {
public:
  std::string do_grouping() const { return "\3"; }
  Char do_thousands_sep() const { return ' '; }
};

int main(int ac, char **av) {
  using std::locale;
  using std::cout;

  // Show how it works to start with
  cout << 123456789 << "\n";

  // Switch it to spacey mode
  locale oldLoc =
    cout.imbue(locale(cout.getloc(), new MyFacet<char>));

  // How does it work now?
  cout << 456789123 << "\n";

  // You probably want to clean up after yourself
  cout.imbue(oldLoc);

  // Does it still work?
  cout << 789123456 << "\n";
}