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android - 通过 HTTP 身份验证将凭据传递到服务器并获取响应的完整指南

转载 作者:塔克拉玛干 更新时间:2023-11-03 01:10:09 29 4
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所以我们知道如何进行 http get 和 post 连接。 http://exampledepot.com/egs/java.net/pkg.html我们希望将凭据(uname,passwd)传递给任何 Web 服务器以访问 url 或获取响应。而且我们不能将它作为 post 参数传递。所以看看@这个非常简单的代码,它完成了这一切。

最佳答案

 try
{
// Creatin the connection
URL url = new URL("http://yoururl");
URLConnection conn = url.openConnection();

//sendin the base64 encoded credentials thru d header
conn.setRequestProperty(
"Authorization",
"Basic "+ BasicAuth.encode(username, password));

// Get the response
BufferedReader rd = new BufferedReader(
new InputStreamReader(conn.getInputStream()));

//readin d response till d end
while ((line = rd.readLine()) != null) {
// Process line...
Log.v("", line);
}

rd.close();
}
catch (Exception e) { }

为了对凭据进行编码,我使用了一个名为“BasicAuth.java”的简单外部类,您可以将其添加到您的项目中。BasicAuth.java

public class BasicAuth {
private BasicAuth() {}

// conversion table
private static byte[] cvtTable = {
(byte)'A', (byte)'B', (byte)'C', (byte)'D', (byte)'E',
(byte)'F', (byte)'G', (byte)'H', (byte)'I', (byte)'J',
(byte)'K', (byte)'L', (byte)'M', (byte)'N', (byte)'O',
(byte)'P', (byte)'Q', (byte)'R', (byte)'S', (byte)'T',
(byte)'U', (byte)'V', (byte)'W', (byte)'X', (byte)'Y',
(byte)'Z',
(byte)'a', (byte)'b', (byte)'c', (byte)'d', (byte)'e',
(byte)'f', (byte)'g', (byte)'h', (byte)'i', (byte)'j',
(byte)'k', (byte)'l', (byte)'m', (byte)'n', (byte)'o',
(byte)'p', (byte)'q', (byte)'r', (byte)'s', (byte)'t',
(byte)'u', (byte)'v', (byte)'w', (byte)'x', (byte)'y',
(byte)'z',
(byte)'0', (byte)'1', (byte)'2', (byte)'3', (byte)'4',
(byte)'5', (byte)'6', (byte)'7', (byte)'8', (byte)'9',
(byte)'+', (byte)'/'
};

/**
* Encode a name/password pair appropriate to
* use in an HTTP header for Basic Authentication.
* name the user's name
* passwd the user's password
* returns String the base64 encoded name:password
*/
static String encode(String name,
String passwd) {
byte input[] = (name + ":" + passwd).getBytes();
byte[] output = new byte[((input.length / 3) + 1) * 4];
int ridx = 0;
int chunk = 0;

/**
* Loop through input with 3-byte stride. For
* each 'chunk' of 3-bytes, create a 24-bit
* value, then extract four 6-bit indices.
* Use these indices to extract the base-64
* encoding for this 6-bit 'character'
*/
for (int i = 0; i < input.length; i += 3) {
int left = input.length - i;

// have at least three bytes of data left
if (left > 2) {
chunk = (input[i] << 16)|
(input[i + 1] << 8) |
input[i + 2];
output[ridx++] = cvtTable[(chunk&0xFC0000)>>18];
output[ridx++] = cvtTable[(chunk&0x3F000) >>12];
output[ridx++] = cvtTable[(chunk&0xFC0) >> 6];
output[ridx++] = cvtTable[(chunk&0x3F)];
} else if (left == 2) {
// down to 2 bytes. pad with 1 '='
chunk = (input[i] << 16) |
(input[i + 1] << 8);
output[ridx++] = cvtTable[(chunk&0xFC0000)>>18];
output[ridx++] = cvtTable[(chunk&0x3F000) >>12];
output[ridx++] = cvtTable[(chunk&0xFC0) >> 6];
output[ridx++] = '=';
} else {
// down to 1 byte. pad with 2 '='
chunk = input[i] << 16;
output[ridx++] = cvtTable[(chunk&0xFC0000)>>18];
output[ridx++] = cvtTable[(chunk&0x3F000) >>12];
output[ridx++] = '=';
output[ridx++] = '=';
}
}
return new String(output);
}

}

关于android - 通过 HTTP 身份验证将凭据传递到服务器并获取响应的完整指南,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1969389/

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