android - 使用 ksoap2-android 订阅共享点网络服务时出现身份验证错误

Question

我正在编写一个 Android 应用程序，它将在 sharepoint 2010 中使用 lists.amx 服务的 getlist() 方法。我正在使用 ksoap2-android 来处理我的 soap 消息。当我尝试进行身份验证时，我得到一个 xmlpullparser exception expected START_TAG...为什么以下代码不会对 Sharepoint 服务器进行身份验证？

这是我的代码:

public class SharepointList extends Activity {
private static final String SOAP_ACTION = "http://schemas.microsoft.com/sharepoint/soap/GetList";
private static final String METHOD_NAME = "GetList";
private static final String NAMESPACE = "http://schemas.microsoft.com/sharepoint/soap/" ;
private static final String URL = "http://<ip of sharepoint server>/_vti_bin/lists.asmx";

private TextView result;
private Button btnSubmit;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    result = (TextView)findViewById(R.id.textView1);
    btnSubmit = (Button)findViewById(R.id.button1);
    btnSubmit.setOnClickListener(new OnClickListener(){
        public void onClick(View v) {
            if(v.getId() == R.id.button1)
            {
                String list = getMobileTestList();
                result.setText(list);
            }

        }

    });


}
private String getMobileTestList()
{
    PropertyInfo pi = new PropertyInfo();
    pi.setName("listName");
    pi.setValue("Mobile Test List");

    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    request.addProperty(pi);

    String authentication = android.util.Base64.encodeToString("username:password".getBytes(), android.util.Base64.DEFAULT);
    List<HeaderProperty> headers = new ArrayList<HeaderProperty>();
    headers.add(new HeaderProperty("Authorization","Basic " +authentication));
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);


    HttpTransportSE transport = new HttpTransportSE(URL);
    try
    {
        transport.debug = true;
        transport.call(SOAP_ACTION, envelope, headers);
        //transport.call(SOAP_ACTION, envelope);
        Object result = envelope.getResponse();
        return result.toString();

    }
    catch(Exception e)
    {
        return e.toString();
    }
}
}

这是 transport.requestdump(前面的 '<' 已删除):

• v:信封 xmlns:i="http://www.w3.org/2001/XMLSchema-instance"xmlns:d="http://www.w3.org/2001/XMLSchema"xmlns:c= "http://schemas.xmlsoap.org/soap/encoding/"xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
  • v:标题/>
  • v:正文>
    • GetList xmlns="http://schemas.microsoft.com/sharepoint/soap/"id="o0"c:root="1">
      • listName i:type="d:string">移动测试列表
  • /GetList>
  • /v:正文>
• /v:信封>

这是 transport.responsedump(前面的 '<' 已删除):

• !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd">
  • HTML>
  • 负责人>
    • TITLE>错误的请求
    • META HTTP-EQUIV="Content-Type"Content="text/html; charset=us-ascii">
  • /头>
  • body >
    • h2>错误的请求 - 无效的主机名
    • hr> p>HTTP 错误 400。请求主机名无效。

  • /正文>
• /HTML>

Answer 1

也许可以尝试以下方法:

String authentication = android.util.Base64.encodeToString("username:password".getBytes(), android.util.Base64.NO_WRAP);

默认情况下，Android Base64 实用程序会在编码字符串的末尾添加一个换行符。这会使 HTTP header 无效并导致“错误请求”。

Base64.NO_WRAP 标志可以防止这种情况并保持 header 的完整性。