gpt4 book ai didi

android - 未发送 HttpGet 参数

转载 作者:塔克拉玛干 更新时间:2023-11-03 01:04:03 25 4
gpt4 key购买 nike

我在 android 上使用 apache.http,大部分工作正常,但是当我尝试使用参数执行 get 请求时,这些参数也不会被发送。我究竟做错了什么?这是代码

HttpClient httpclient = new DefaultHttpClient();
HttpUriRequest request = new HttpGet(uri);

HttpParams p = new BasicHttpParams();
p.setParameter("param", "value");
request.setParams(p);

request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");

HttpResponse response = null;

try {
response = httpclient.execute(request);
} catch (ClientProtocolException e) {
e.printStackTrace();
}

在服务器上我只得到这个没有参数

GET /api/v1/activity/ HTTP/1.1
Host: example.com
Connection: Keep-Alive
Accept-Encoding: gzip
Accept: application/json, text/javascript, */*; q=0.01

有什么想法吗?

最佳答案

您必须修改 URI,如下所示:

HttpClient httpclient = new DefaultHttpClient();

String url = "http://example.com";
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add( new BasicNameValuePair( "param", "value" ) );
URI uri = new URI( url + "?" + URLEncodedUtils.format( params, "utf-8" );

HttpUriRequest request = new HttpGet(uri);

request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");

HttpResponse response = null;

try {
response = httpclient.execute(request);
} catch (ClientProtocolException e) {
e.printStackTrace();
}

关于android - 未发送 HttpGet 参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15282240/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com