linux - 调用脚本文件时如何提示建议

Question

我必须为 linux-box 编写一个脚本，它从命令行获取输入 sudo build_all.sh -vmware yes|no nic bridged|host_only -ipaddress xx.xx.xx.xx|dhcp -arch=ARM|x86 ，我想知道输入输入时是否有办法获得建议。对于前。

如果我输入 sudo build_all.sh然后按 Tab我得到了类似 -vmware 的建议输入-vmware后我又树了Tab我提示了 Yes No .

有什么办法吗？

Answer 1

这称为 bash 补全。您可以在/etc/bash_completion.d/中找到许多示例。 bash_completion 函数需要加载到您的 shell 才能工作。这是一个让你开始的例子

# Bash completion must to be loaded when shell starts
# Recommended location is /etc/bash_completion.d/build_all.sh
# or added to ~/.bashrc
# Then load with . /etc/bash_completion.d/build_all.sh
# or with . ~/.bashrc
# New instances of bash will have already sourced it. 
# The file name build_all.sh may be too common, and result in unwanted tab
# completion for build_all.sh from other projects. 

_build_all.sh(){
    local cur
    COMPREPLY=()
    _get_comp_words_by_ref cur

    case  $COMP_CWORD in
        1) COMPREPLY=( $( compgen -W '-vmware' -- "$cur" ) ) ;;
        2) COMPREPLY=( $( compgen -W 'no yes' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;

        3) COMPREPLY=( $( compgen -W '-nic' -- "$cur" ) ) ;;
        4) COMPREPLY=( $( compgen -W 'host_only bridged' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;

        5) COMPREPLY=( $( compgen -W '-ipaddress' -- "$cur" ) ) ;;
        6) COMPREPLY=( $( compgen -W 'dhcp xx.xx.xx.xx' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;

        7) COMPREPLY=( $( compgen -W '-arch' -- "$cur" ) ) ;;
        8) COMPREPLY=( $( compgen -W 'x86 ARM' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;
    esac
    return 0

} &&
complete -F _build_all.sh build_all.sh