regex - 查找 "StringBetween"整个目录 linux cli

Question

我有一个运行着 iredmail 的邮件服务器。

我们每天发送几封时事通讯，“退回”的在 vmail 文件夹中。

我想在不使用 smtp 的情况下从这些文件中提取“id”，因为我已经在本地拥有整个邮件内容。

"http://www.myserver.com/index.php?m=xxxxxxxxxx"

我现在想遍历目录中的所有文件并在每个文件中找到第一次出现的“xxxxxxxxx”并将其保存到文本文件中，这样我就可以从邮件列表数据库中删除这些 ID。

如果可能，通过 CLI。

提前致谢。

Answer 1

尝试使用下面的命令来查找每个文件中第一次出现的 id，

find . -maxdepth 1 -type f -exec grep -oP -m 1 '(?<=index\.php\?m\=)[^"]*' {} \; | sort -u

解释:

find         # command to find files are directories

.            # current directory(path on which the operation of find command is going to takes place)

-maxdepth 1  # don't search inside subdirectories.(ie; search only in the current directory)

-type f      # Only files

-exec grep -oP -m 1 '(?<=index\.php\?m\=)[^"]*' {} \;  # execute the grep command on only the founded files.

            -oP                          # (-o)print only the match,(-P) Perl-regex.
            -m 1                         # Grep to stop after first match occurs on each file.
            (?<=index\.php\?m\=)[^"]*    # A lookbehind is used here. It matches the text after `index.php?m=` upto the first occurrence of `"`. It helps to match the id's.
             {}                          # Founded files.
             \;                          # stops the find command.

sort -u      #  print only the unique id's.