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java - ListView 只显示一项

转载 作者:塔克拉玛干 更新时间:2023-11-03 00:45:01 26 4
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我正在尝试在 ListView 中显示 Json。我正在使用 Map 来检索值。列表中仅显示第一项。 BaseAdapter 中的 getCount() 每次返回大小为 1,即使 Map 中有多个值。

MyContactAdapter2.java

public class MyContactAdapter2 extends BaseAdapter {
List<Map<String, List<EffectList>>> contactList;
Context context;
private LayoutInflater mInflater;


// Constructors
public MyContactAdapter2(Context context, List<Map<String, List<EffectList>>> objects) {

this.context = context;
this.mInflater = LayoutInflater.from(context);
contactList = objects;
}

public MyContactAdapter2() {
System.out.println("hai");
}

@Override
public int getCount() {
int count = contactList.size();
System.out.println("Count size" + count);
return count;
}

@Override
public Map<String, List<EffectList>> getItem(int position) {
return contactList.get(position);
}


@Override
public long getItemId(int position) {
return 0;
}


@Override
public View getView(int position, View convertView, ViewGroup parent) {


System.out.println(10);


final MyContactAdapter2.ViewHolder vh;
if (convertView == null) {
View view = mInflater.inflate(R.layout.get_layout_row_view, parent, false);
vh = MyContactAdapter2.ViewHolder.create((RelativeLayout) view);
view.setTag(vh);

} else {
vh = (MyContactAdapter2.ViewHolder) convertView.getTag();
}





for (Map<String, List<EffectList>> map : contactList) {
for (Map.Entry<String, List<EffectList>> entry : map.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
System.out.println("key :" + key + "value :" + value);

EffectList item = getItem(position).get(key).get(0);

vh.textViewName.setText(item.getEffectsId());
vh.textViewEmail.setText(item.getEffectsName());

}
}


return vh.rootView;
}


private static class ViewHolder {
public final RelativeLayout rootView;
public final ImageView imageView;
public final TextView textViewName;
public final TextView textViewEmail;

private ViewHolder(RelativeLayout rootView, ImageView imageView, TextView textViewName, TextView textViewEmail) {
this.rootView = rootView;
this.imageView = imageView;
this.textViewName = textViewName;
this.textViewEmail = textViewEmail;
}

public static MyContactAdapter2.ViewHolder create(RelativeLayout rootView) {
ImageView imageView = (ImageView) rootView.findViewById(R.id.imageView);
TextView textViewName = (TextView) rootView.findViewById(R.id.textViewName);
TextView textViewEmail = (TextView) rootView.findViewById(R.id.textViewEmail);
return new MyContactAdapter2.ViewHolder(rootView, imageView, textViewName, textViewEmail);
}
}
}

我在迭代 map 时做错了什么吗?

这是我要解析的 Json。

{
"effect_list": [{
"1":[
{
"effects_id":"1",
"effects_name":"Band 1"
},
{
"effects_id":"2",
"effects_name":"Band 2"
}


],
"2": [
{
"effects_id":"4",
"effects_name":"Background Blur"
},
{
"effects_id":"5",
"effects_name":"Blemish Removal"
}
]
}]
}

我想显示 1(0) 和 2(0)。 ListView

中仅显示 1(0) 个 ("effects_id":"1")

为什么我的 getCount() 大小总是 1,即使它有多个值?

最佳答案

试试这个,

public class MyContactAdapter2 extends BaseAdapter {
List<EffectList> contacts;
Context context;
private LayoutInflater mInflater;


// Constructors
public MyContactAdapter2(Context context, List<Map<String, List<EffectList>>> objects) {

this.context = context;
this.mInflater = LayoutInflater.from(context);
this.contacts = new ArrayList<>();
Map<String, List<EffectList>> map = objects.get(0);
Set<String> keySet = map.keySet();
Iterator<String> iterator = keySet.iterator();
while (iterator.hasNext()) {
this.contacts.addAll(map.get(iterator.next()));
}
}

public MyContactAdapter2() {
System.out.println("hai");
}

@Override
public int getCount() {
int count = contacts.size();
return count;
}

@Override
public EffectList getItem(int position) {
return contacts.get(position);
}


@Override
public long getItemId(int position) {
return 0;
}


@Override
public View getView(int position, View convertView, ViewGroup parent) {


System.out.println(10);


final MyContactAdapter2.ViewHolder vh;
if (convertView == null) {
View view = mInflater.inflate(R.layout.get_layout_row_view, parent, false);
vh = MyContactAdapter2.ViewHolder.create((RelativeLayout) view);
view.setTag(vh);

} else {
vh = (MyContactAdapter2.ViewHolder) convertView.getTag();
}
EffectList item = getItem(position);

vh.textViewName.setText(item.getEffectsId());
vh.textViewEmail.setText(item.getEffectsName());


return vh.rootView;
}


private static class ViewHolder {
public final RelativeLayout rootView;
public final ImageView imageView;
public final TextView textViewName;
public final TextView textViewEmail;

private ViewHolder(RelativeLayout rootView, ImageView imageView, TextView textViewName, TextView textViewEmail) {
this.rootView = rootView;
this.imageView = imageView;
this.textViewName = textViewName;
this.textViewEmail = textViewEmail;
}

public static MyContactAdapter2.ViewHolder create(RelativeLayout rootView) {
ImageView imageView = (ImageView) rootView.findViewById(R.id.imageView);
TextView textViewName = (TextView) rootView.findViewById(R.id.textViewName);
TextView textViewEmail = (TextView) rootView.findViewById(R.id.textViewEmail);
return new MyContactAdapter2.ViewHolder(rootView, imageView, textViewName, textViewEmail);
}
}
}

关于java - ListView 只显示一项,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41499514/

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