c++ - ideone 不显示任何输出

Question

这段代码有问题http://www.spoj.com/problems/BASE/它在 windows 和 linux 上运行良好，但是当我在 ideone 上运行它时，它没有显示任何输出。谁能告诉我这背后的原因是什么？

#include<stdio.h>
#include<math.h>
#include<string.h>
#include<string>
#include<iostream>

using namespace std;

long int convert_base10(char *num, int base)
{
int len, dig;
long int result = 0;
len = strlen(num);
//    printf("len = %d\n", len);
// converting to base 10
for(int i=0; i<len; i++)
{
    if((num[len-i-1] >= 'A') && (num[len-i-1] <= 'F'))
        dig = num[len-i-1] - 55;
    else
        dig = num[len-i-1] - 48;
    result +=  (dig * pow(base, i));
  //        printf("num[%d] = %d\n", len-i-1, dig);
}
return result;
}

void convert_basei(long int num, int base, string &result1)
{
bool error = false;
int pos = 6;
char result[7], rem;
// initially storing space on all position
for(int i=0; i<7; i++)
    result[i] = ' ';
while(num)
{
    if((num % base) >= 10)
        rem = (num % base) + 55;
    else
        rem = (num % base) + 48;
    result[pos] = rem;//printf("result[%d] = %c\n", pos, rem);
    num /= base;//    printf("quotient = %d\n", num);
    pos--;
    if(pos < 0 && num > 0)
    {
        error = true;
        break;
    }

}
if(error == true)
   result1 = "  ERROR";
else
    result1 = result;
//    cout<<"result = "<<result1<<endl;
}

int main()
{
char num[7];
string result;
int base1, base2;
while(scanf("%s%d%d", num, &base1, &base2) == 3)
{
//        printf("num = %s\nbase1 = %d\nbase2 = %d\n", num, base1, base2);
    long int temp = convert_base10(num, base1);
//        printf("temp = %ld\n", temp);
    convert_basei(temp, base2, result);
    cout<<result<<endl;
}
return 0;
}

Answer 1

替换这段代码:

while(scanf("%s%d%d", num, &base1, &base2) == 3)
{
    long int temp = convert_base10(num, base1);
    convert_basei(temp, base2, result);
    cout<<result<<endl;
}

有了这段代码，谜团就会消失:

printf("trying to get input\n");
while(scanf("%s%d%d", num, &base1, &base2) == 3)
{
    printf("got some input\n");
    long int temp = convert_base10(num, base1);
    convert_basei(temp, base2, result);
    cout<<result<<endl;
}
printf("got no input\n");