linux - 在 shell 脚本中更正 if ..elif 中的输出

Question

我有以下销售代码

#!/bin/sh
echo "hello"
echo "enter the salutation $abc"
read -r abc
if [ "$abc" = "1" ]
then
 echo "Hiiii"
elif [ "$abc" = "2" ]
then
echo "haaaaa"
fi
echo "enter name $xyz"
read -r xyz
if 
if [ "$xyz" = "1" ]
then
 echo "Chris"
elif [ "$xyz" = "2" ]
then
echo "Morris"
fi
echo "you had put salutation as" "$abc"
echo "you entered name as " "$xyz"

我需要最终打印出来

 you had put salutation as Hii
 you entered name as chris

我得到的是

 you had put salutation as 1
 you entered name as 1

Any help? Do I need to mention the final statement inside the if elif statement?

Answer 1

问题出在你的 echo 语句上:

echo "Hiiii"
echo "haaaaa"
echo "Chris"
echo "Morris"

您只是打印字符串，而不是将其存储在您可以显示为预期输出的变量中:

echo "you had put salutation as" "$abc"
echo "you entered name as " "$xyz"

当您输入时，存储在 abc 和 xyz 中的值将是 1 和 1。使用变量来存储值并在需要时显示它们。比如，将 echo 替换为以下内容:

disp_sal="Hiiii" disp_sal="haaaaa"

disp_name="克里斯"disp_name="莫里斯"

还有，

echo "you had put salutation as" "$disp_sal"
echo "you entered name as " "$disp_name"