linux - 使 Selenium 在超时错误后继续

Question

我有一个返回网站列表标题的代码。有时，一个网站需要花费大量的时间来加载，所以当这种情况发生时，会出现超时错误提示。我想让它在发生此类错误时，程序继续运行而不是完全停止。

代码是:

from pyvirtualdisplay import Display
from time import sleep
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
from selenium import webdriver
from selenium.webdriver.firefox.options import Options
display = Display(visible=0, size(800,600))
display.start()
driver = webdriver.Firefox(executable_path='/usr/local/lib/geckodriver/geckodriver')
driver.set_page_load_timeout(60)
driver.get('https://google.com')
print(driver.title)

以下代码是在 60 秒后页面未加载时发生超时的原因:

driver.set_page_load_timeout(60)

当60秒过去后，程序停止并提示超时错误。我希望它继续使用下一个 url。

Answer 1

即使出现 page_load_timeout 错误，要迭代 List url，您可以使用以下解决方案:

• 代码块:

  from selenium import webdriver
  from selenium.common.exceptions import TimeoutException
  
  urls = ["https://www.booking.com/hotel/in/the-taj-mahal-palace-tower.html?label=gen173nr-1FCAEoggJCAlhYSDNiBW5vcmVmaGyIAQGYATG4AQbIAQzYAQHoAQH4AQKSAgF5qAID;sid=338ad58d8e83c71e6aa78c67a2996616;dest_id=-2092174;dest_type=city;dist=0;group_adults=2;hip_dst=1;hpos=1;room1=A%2CA;sb_price_type=total;srfid=ccd41231d2f37b82d695970f081412152a59586aX1;srpvid=c71751e539ea01ce;type=total;ucfs=1&#hotelTmpl", "https://www.google.com/"]
  driver = webdriver.Chrome(executable_path=r'C:\WebDrivers\chromedriver.exe')
  driver.set_page_load_timeout(2)
  for url in urls:
      try :
          driver.get(url)
          print("URL successfully Accessed ... Proceeding with other tasks !!!")
          # perform other operations within the url
      except TimeoutException as e:
          print("Page load Timeout Occured ... moving to next item !!!")
  driver.quit()
  

• 控制台输出:

  Page load Timeout Occured ... moving to next item !!!
  Page load Timeout Occured ... moving to next item !!!
  

• 注意:

  • set_page_load_timeout(2) 用于重现页面加载超时，仅供演示之用。
  • urls 的列表仅用于演示目的。

You can find a detailed discussion on page load timeout in How to set the timeout of 'driver.get' for python selenium 3.8.0?