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c++ - 平衡二叉搜索树 (BST)

转载 作者:塔克拉玛干 更新时间:2023-11-03 00:21:24 26 4
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我正在尝试创建一个 balance_bst(bstNode root) 函数,但我在实现方面遇到了困难。

我将该函数实现为模板函数,因为我的 bstNode 类是模板类。

这是我的(部分)代码:

template<class Item, class  Key>
class bstNode{
public:
//Constructor
bstNode(const Item& init_data = Item(), const Key& init_key = Key(), bstNode<Item, Key>* l_child = NULL, bstNode<Item, Key>* r_child = NULL){
data_field = init_data;
key_field = init_key;
l_ptr = l_child;
r_ptr = r_child;
}
//Destructor
~bstNode(){
data_field = 0;
key_field = 0;
l_ptr = r_ptr = NULL;
}
//Basic Member Functions
bstNode<Item, Key>*& left( ) { return l_ptr; } //returns left child pointer by reference
bstNode<Item, Key>*& right( ) { return r_ptr; } //returns right child pointer by reference
bstNode<Item, Key>* left( ) const { return l_ptr; } //returns left child pointer by reference
bstNode<Item, Key>* right( ) const { return r_ptr; } //returns right child pointer by reference
const Item& data() const{ return data_field; } //returns reference to data_field
const Key& key()const { return key_field; }
Item& data() { return data_field; } //returns reference to data_field
Key& key() { return key_field; }
void set_data(const Item& new_data){ data_field = new_data; } //sets data_field to new_data
void set_key(const Key& new_key){ key_field = new_key; } //sets key_field to new_key
void set_left(bstNode* new_left){ l_ptr = new_left; } //sets left child pointer to new_left
void set_right(bstNode* new_right){ r_ptr = new_right; } //sets right child pointer to new_right

private:
bstNode<Item, Key> *l_ptr, //pointer to left child node
*r_ptr; //pointer to right child node
Item data_field;
Key key_field;
};

template<class Item, class Key>
void balance_bst(bstNode<Item, Key>*& root){ //unfinished

std::vector< bstNode<Item, Key>* > nodes;
sorter(root, nodes);
size_t i = nodes.size()/2; //size() divided by 2 will yield
//index of middle element of vector for
//odd-isized arrays and the greater of the
//middle two elements for an even-sized array

while(i>=0){
root->set_key(nodes[i]->key());
root->set_data(nodes[i]->data());
//.....MORE CODE HERE: recursive call??

}


}

template<class Item, class Key>
void sorter(bstNode<Item, Key>*& root, std::vector<bstNode<Item, Key>* >& tree_nodes){
if(root == NULL)
return;
sorter(root->left(), tree_nodes);
tree_nodes.push_back(root);
sorter(root->right(), tree_nodes);
}

我一直在搞乱实际的 balance_bst 函数,并认为递归是显而易见的解决方案,但我似乎无法理解这个问题......

sorter 基本上使用中序处理算法将 BST 的元素插入到 vector 中。所以只要“root”是一个指向二叉搜索树根的指针(即节点左子树的所有键值都小于节点的键值,节点右子树的所有键值都大于nodes),那么插入到vector中的节点将按升序排序。

然后,为了创建一棵平衡树,我将节点插入到树根 vector 的中心,然后应该能够递归地插入左子节点和右子节点,它们将位于树的中间 vector 的左半部分和 vector 右半部分的中间。

注意:我知道这是使用整数除法,也就是说,7/2 = 3,这将是大小为 7 的数组的中间元素的索引。对于偶数大小的数组,上面实现的算法将在 vector 中间找到两个元素中较大者的索引。

无论如何,欢迎和鼓励任何建议或意见!提前致谢。

编辑:我想问的是如何实现一个函数来平衡二叉搜索树?(平衡 BST 是在给定节点数的情况下具有最小深度的 BST。)

最佳答案

平衡二叉搜索树也称为AVL树.

This wikipedia link对解决平衡问题有很好的解释。

我发现平衡树的最简单方法是在插入过程中。这是一个带有辅助函数(用于各种旋转情况)和 AVLNode 类的递归插入。

        bool avl_insert(AVLNode*& subRoot, const int &newData, bool &taller)
{
bool result = true;
if(!subRoot){
subRoot = new AVLNode(newData);
taller = true;
}
else if(newData == subRoot->getData()){
result = false;
taller = false;
}
else if(newData < subRoot->getData()){
result = avl_insert(subRoot->getLeft(), newData, taller);
if(taller)
switch(subRoot->getBalance()){
case -1:
left_balance(subRoot);
taller = false;
break;
case 0:
subRoot->setBalance(-1);
break;
case 1:
subRoot->setBalance(0);
taller = false;
break;
}
}
else{
result = avl_insert(subRoot->getRight(), newData, taller);
if(taller)
switch(subRoot->getBalance()){
case -1:
subRoot->setBalance(0);
taller = false;
break;
case 0:
subRoot->setBalance(1);
break;
case 1:
right_balance(subRoot);
taller = false;
break;
}
}
return result;
}

辅助函数

        void right_balance(AVLNode *&subRoot)
{
AVLNode *&right_tree = subRoot->getRight();
switch(right_tree->getBalance()){
case 1:
subRoot->setBalance(0);
right_tree->setBalance(0);
rotate_left(subRoot); break;
case 0:
cout<<"WARNING: program error in right_balance"<<endl; break;
case -1:
AVLNode *subTree = right_tree->getLeft();
switch(subTree->getBalance()){
case 0:
subRoot->setBalance(0);
right_tree->setBalance(0);break;
case -1:
subRoot->setBalance(0);
right_tree->setBalance(1); break;
case 1:
subRoot->setBalance(-1);
right_tree->setBalance(0);break;
}
subTree->setBalance(0);
rotate_right(right_tree);
rotate_left(subRoot); break;
}
}
void left_balance(AVLNode *&subRoot)
{
AVLNode *&left_tree = subRoot->getLeft();
switch(left_tree->getBalance()){
case -1:
subRoot->setBalance(0);
left_tree->setBalance(0);
rotate_right(subRoot); break;
case 0:
cout<<"WARNING: program error in left_balance"<<endl; break;
case 1:
AVLNode *subTree = left_tree->getRight();
switch(subTree->getBalance()){
case 0:
subRoot->setBalance(0);
left_tree->setBalance(0);break;
case -1:
subRoot->setBalance(0);
left_tree->setBalance(1); break;
case 1:
subRoot->setBalance(-1);
left_tree->setBalance(0);break;
}
subTree->setBalance(0);
rotate_left(left_tree);
rotate_right(subRoot); break;
}
}

void rotate_left(AVLNode *&subRoot)
{
if(subRoot == NULL || subRoot->getRight() == NULL)
cout<<"WARNING: program error detected in rotate_left"<<endl;
else{
AVLNode *right_tree = subRoot->getRight();
subRoot->setRight(right_tree->getLeft());
right_tree->setLeft(subRoot);
subRoot = right_tree;
}
}
void rotate_right(AVLNode *&subRoot)
{
if(subRoot == NULL || subRoot->getLeft() == NULL)
cout<<"WARNING: program error detected in rotate_left"<<endl;
else{
AVLNode *left_tree = subRoot->getLeft();
subRoot->setLeft(left_tree->getRight());
left_tree->setRight(subRoot);
subRoot = left_tree;
}
}

AVLNode类

class AVLNode
{
public:
AVLNode()
{
previous = NULL;
next = NULL;
}
AVLNode(int newData){
data = newData;
previous = NULL;
balance=0;
next = NULL;
}
~AVLNode(){}
void setBalance(int b){balance = b;}
int getBalance(){return balance;}
void setRight(AVLNode* newNext){next = newNext;}
void setLeft(AVLNode* newPrevious){previous = newPrevious;}
AVLNode* getRight() const{return next;}
AVLNode* getLeft() const{return previous;}
AVLNode*& getRight(){return next;}
AVLNode*& getLeft(){return previous;}
int getData() const{return data;}
int& getData(){return data;}
void setData(int newData){data = newData;}
void setHeight(int newHeight){ height = newHeight;}
int getHeight(){return height;}
private:
AVLNode* next;
AVLNode* previous;
int balance;
int height;
int data;
};

希望这对您有所帮助!

关于c++ - 平衡二叉搜索树 (BST),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10439681/

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