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android - 如何在android中使用GSON解析以下JSON?

转载 作者:塔克拉玛干 更新时间:2023-11-03 00:19:49 26 4
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因为 keysArray (A,B,C) 是 dynamiccores 具有相同的对象名称?请帮忙!!!

{

"result":"success",

"keysArray":[
"A",
"B",
"C",
"D",
"E"
],

"cores":{

"A":[{"key":"value"}],
"B":[{"key":"value"}],
"C":[{"key":"value"}],
"D":[{"key":"value"}],
"E":[{"key":"value"}]
}
}

最佳答案

我是这样实现的。

String responseStr = //JsonResponse here
Type type = new TypeToken<GetMainResponse>() {}.getType();
GetMainResponse getMainResponse = new GsonBuilder().excludeFieldsWithModifiers(Modifier.TRANSIENT).create().fromJson(responseStr, type);

int size = getMainResponse.getKeysArray().size();
for (int i = 0; i < size; i++) {
JSONArray jCoreIngredients = new JSONObject(responseStr)
.getJSONArray(getMainResponse.getKeysArray().get(i));
String innerStr = jCoreIngredients.toString();
Type type2 = new TypeToken<ArrayList<GetMainResponse.InnerCores>>() {}.getType();
ArrayList<GetMainResponse.InnerCores> ingredientsInner = new GsonBuilder().excludeFieldsWithModifiers(Modifier.TRANSIENT).create().fromJson(innerStr, type2);
}

//And this is my POJO

public class GetMainResponse{
String result;
ArrayList<String> keysArray;
Cores cores;

public String getResult() { return result; }

public void setResult(String result) { this.result = result; }

public ArrayList<String> getKeysArray() { return keysArray; }

public void setKeysArray(ArrayList<String> keysArray) { this.keysArray = keysArray; }

public Data getCores() { return data; }

public void setCores(Cores cores) { this.cores = cores; }

public class Cores {

// No declaration and not getter setter here.

public class InnerCores {
String key;

public String getKey() { return key; }

public void setKey(String result) { this.key = key; }

}
}

任何建议:)

关于android - 如何在android中使用GSON解析以下JSON?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41355969/

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