android - 如何在Service和Activity之间传递复杂的数据？

Question

我们如何在服务和 Activity 之间传递复杂数据(例如，员工对象)？

在这里，Service 和 Activity 在不同的包中。可能是不同的应用程序。

Answer 1

• 首先序列化你要传递的对象。
• 将序列化对象放入 intent extras 中。
• 在接收端，获取序列化后的对象，反序列化即可。

说，

 Employee employee = new Employee();

然后，

intent.putExtra("employee", serializeObject(employee));

接收时，

byte[] sEmployee = extras.getByteArray("employee");

employee = (Employee) deserializeObject(sEmployee);

仅供引用，

public static byte[] serializeObject(Object o) throws Exception,IOException {
    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    ObjectOutput out = new ObjectOutputStream(bos);
    try {
        out.writeObject(o);
        // Get the bytes of the serialized object
        byte[] buf = bos.toByteArray();

        return buf;
    } catch (IOException e) {
        Log.e(LOG_TAG, "serializeObject", e);
        throw new Exception(e);
    } finally {
        if (out != null) {
            out.close();
        }
    }
}

public static Object deserializeObject(byte[] b)
        throws StreamCorruptedException, IOException,
        ClassNotFoundException, Exception {
    ObjectInputStream in = new ObjectInputStream(
            new ByteArrayInputStream(b));
    try {
        Object object = in.readObject();
        return object;
    } catch (Exception e) {
        Log.e(LOG_TAG, "deserializeObject", e);
        throw new Exception(e);
    } finally {
        if (in != null) {
            in.close();
        }
    }
}