linux - 用awk解析多行

Question

我有一个多行输出，像这样:

foo: some text
    goes here
    and here
    and here
bar: more text
    goes here
    and here
xyz: and more...
    and more...
    and more...

文本的格式与这里显示的完全一样。我感兴趣的文本的“组/节”在行首之后开始，并在下一个文本开始之前的行结束。

在这个例子中，grouls 是 foo 和 bar 之前的所有文本。然后是 bar 和 xyz 之前的所有文本。最后，xyz 直到结束。

Answer 1

输入

$ cat file
foo: some text
    goes here
    and here
    and here
bar: more text
    goes here
    and here
xyz: and more...
    and more...
    and more...

输出

$ awk '/:/{f=/^foo/}f' file
foo: some text
    goes here
    and here
    and here

如果您想跳过匹配的行

$ awk '/:/{f=/^foo/;next}f' file
    goes here
    and here
    and here

甚至

# Just modify variable search value
# 1st approach
$ awk -v search="foo" '/:/{f=$0~"^"search}f' file
foo: some text
    goes here
    and here
    and here

# 2nd approach
$ awk -v search="foo" '/:/{f=$0~"^"search;next}f' file
    goes here
    and here
    and here