regex - 在特定单词和提到的单词之后打印值

Question

所以我有一个像这样的file.txt

abc, def, class="my_name", this is good
def, hij, this is getting bad, and bad, class="my_class"
trying to achive my goal class="still_looking"

所以我需要一个类的值，即:

my_name
my_class
still_looking

我尝试了 sed 和 grep 但没有成功。

sed "s/[^class=]*,\([^\"]*\),^C/\1/" file.txt

grep -oP '(?<=class)[0-9][a-z][A-Z]+' file.txt

Answer 1

捕获并输出class="字符串后的所有非"字符:

sed 's/.*class="\([^"]*\)".*/\1/' file.txt

或者如果每行有多个 class，使用 grep，:

grep -oP '(?<=class=")[^"]*' file.txt