linux - 将多个参数传递给脚本 linux

Question

我有以下代码，它应该将文件名作为参数，并将它们发送到我的电子邮件地址，该电子邮件地址是从用户名派生的:

#Email Script from linux
#Define username e.g. pp_roman
u="$USER"

#Remove the pp_ and store to variable e.g. roman

u2=${u#"pp_"}

#Define Email portion

em="@workemail.com"

#Combine the username e.g. roman@workemail.com

u3=$u2$em

#Arguments for script

for FILE1 in "$@"
do
    filename="-a $FILE1"
done

##This returns the full string with $filename variables for arguments, and email from $u3

mailx $filename -s "Subject" $u3 < /dev/null

然而，当传递多个参数时，只有最后提到的文件名作为附件发送。如何将多个参数传递给 $filename 变量，所有参数都附加“-a”？

Answer 1

因为您使用的是 bash，所以正确的做法是使用数组。

attachments=()
for f in "$@"
do
    attachments+=(-a "$f")
done

mailx "${attachments[@]}" -s "Subject" "$u3" < /dev/null