c++ - 如何标记(单词)将标点符号分类为空格

Question

基于这个问题很快就结束了:
Trying to create a program to read a users input then break the array into seperate words are my pointers all valid?

我认为可以做一些额外的工作来帮助 OP 澄清问题，而不是结束。

问题:

我想标记用户输入并将标记存储到一个单词数组中。
我想使用标点符号 (.,-) 作为分隔符，因此将其从 token 流中删除。

在 C 中，我会使用 strtok() 将数组分解为标记，然后手动构建数组。
像这样:

主要功能:

char **findwords(char *str);

int main()
{
    int     test;
    char    words[100]; //an array of chars to hold the string given by the user
    char    **word;  //pointer to a list of words
    int     index = 0; //index of the current word we are printing
    char    c;

    cout << "die monster !";
    //a loop to place the charecters that the user put in into the array  

    do
    {
        c = getchar();
        words[index] = c;
    }
    while (words[index] != '\n');

    word = findwords(words);

    while (word[index] != 0) //loop through the list of words until the end of the list
    {
        printf("%s\n", word[index]); // while the words are going through the list print them out
        index ++; //move on to the next word
    }

    //free it from the list since it was dynamically allocated
    free(word);
    cin >> test;

    return 0;
}

行分词器:

char **findwords(char *str)
{
    int     size = 20; //original size of the list 
    char    *newword; //pointer to the new word from strok
    int     index = 0; //our current location in words
    char    **words = (char **)malloc(sizeof(char *) * (size +1)); //this is the actual list of words

    /* Get the initial word, and pass in the original string we want strtok() *
     *   to work on. Here, we are seperating words based on spaces, commas,   *
     *   periods, and dashes. IE, if they are found, a new word is created.   */

    newword = strtok(str, " ,.-");

    while (newword != 0) //create a loop that goes through the string until it gets to the end
    {
        if (index == size)
        {
            //if the string is larger than the array increase the maximum size of the array
            size += 10;
            //resize the array
            char **words = (char **)malloc(sizeof(char *) * (size +1));
        }
        //asign words to its proper value
        words[index] = newword;
        //get the next word in the string
        newword = strtok(0, " ,.-");
        //increment the index to get to the next word
        ++index;
    }
    words[index] = 0;

    return words;
}

如对上述代码提出任何意见，我们将不胜感激。
但是，此外，在 C++ 中实现此目标的最佳技术是什么？

Answer 1

看看boost tokenizer对于在 C++ 上下文中比 strtok() 好得多的东西。