linux - 读取文件中的第一行并将其附加到搜索字符串的第一次出现处并重复直到 EOF

Question

我在一个文本文件中有一个包含以下行的文件，格式如下

"abc": "xyz",
"qwe": "uva",
"asd": "lkj",

和一个格式如下的json文件

{
    "svn-user-id": "passwd"
    "solution-id": 0,
    "cronos-id": "1",
    "solution-state": "active",
  },
{
    "svn-user-id": "passwd"
    "solution-id": 1,
    "cronos-id": "1",
    "solution-state": "active",
  },
{
    "svn-user-id": "passwd"
    "solution-id": 2,
    "cronos-id": "1",
    "solution-state": "active",
  },

现在我想要json的输出如下

{
        "svn-user-id": "passwd"
        "solution-id": 0,
         "abc": "xyz",
        "cronos-id": "1",
        "solution-state": "active",
      },
    {
        "svn-user-id": "passwd"
        "solution-id": 1,
         "qwe": "uva",
        "cronos-id": "1",
        "solution-state": "active",
      },
    {
        "svn-user-id": "passwd"
        "solution-id": 2,
         "asd": "lkj",
        "cronos-id": "1",
        "solution-state": "active",
      },

那么如何使用 bash 实现这一点呢？

我试过以下但它只附加文件的最后一行。

#!/bin/bash
set -x
file=names.txt #file has list of lines as described above
IFS=$'\n'

for l in `cat $file`
        do
        echo $l 
        sed '/"solution-id": 1,/a \'"$l"'' sample.json # json file as described above
        done

Answer 1

这样做就可以了:

#!/bin/bash
#set -x
IFS=$'\n'

declare -a names
names=(`cat names.txt`)

for l in `cat sample.json`
do
    echo $l
    echo $l | grep -P -q solution-id
    if [ $? -eq 0 ]
    then
        echo "    ${names[$i]}"
        let "i+=1"
    fi
done