c++ - 如何在不使用 break 的情况下退出 C++ 中的循环？

Question

我正在编写代码来交换数组中的整数，我想知道如何在不使用 break 语句的情况下退出循环并保持我的逻辑一致。下面是我的代码:

int swapped = 0;
if (arrays[0][first] % 2 == 0)
{
     cout << arrays[0][first] << " is odd " << endl;
     for (int i = 1; i < arraycount; ++i)
     {
         for (int j = 1; j < arrays[i][0] + 1; ++j)
         {
             if (arrays[i][j] % 2 != 0)
             {
                  int temp = arrays[i][j];
                  cout << "Array #" << 1 << " value " << arrays[0][first] << " swapped with "
                          << "Array #" << i << " value " << temp;

                  arrays[i][j] = arrays[0][first];
                  arrays[0][first] = temp;
                  swapped = 1;
                  break;
              }
          }
          if (swapped) {
                break;
          }

Answer 1

使用 goto [我会因此而受到抨击]。

if (arrays[0][first] % 2 == 0)
{
     cout << arrays[0][first] << " is odd " << endl;
     for (int i = 1; i < arraycount; ++i)
     {
         for (int j = 1; j < arrays[i][0] + 1; ++j)
         {
             if (arrays[i][j] % 2 != 0)
             {
                  int temp = arrays[i][j];
                  cout << "Array #" << 1 << " value " 
                          << arrays[0][first] << " swapped with "
                          << "Array #" << i << " value " << temp;

                  arrays[i][j] = arrays[0][first];
                  arrays[0][first] = temp;
                  goto done;
              }
          }
done:
    something;