java - 向 HTTP 请求添加 cookie

Question

我正在尝试添加一个带有 GUID 的 cookie 来识别用户，但是当我在测试脚本上运行代码时，它似乎没有发送任何 cookie。

我的 Java 代码:

    public void search(String q, int o) {
    final String query = q;
    final int offset = o;
    Thread searchThread = new Thread() {
        public void run() {
            try {
                DefaultHttpClient httpClient = new DefaultHttpClient();
                BasicHttpContext httpContext = new BasicHttpContext();
                CookieStore cookieStore = new BasicCookieStore();
                httpContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);
                cookieStore.addCookie(new BasicClientCookie("remixsid", guid));
                httpClient.setCookieStore(cookieStore);
                HttpPost httpPost = new HttpPost("http://192.168.1.43/test/test.php?section=audio&q=" + URLEncoder.encode(query, HTTP.UTF_8) + "&offset=" + offset);
                //HttpPost httpPost = new HttpPost("http://vkontakte.ru/gsearch.php?section=audio&q=" + URLEncoder.encode(query, HTTP.UTF_8) + "&offset=" + offset);
                HttpResponse response = httpClient.execute(httpPost, httpContext);
                String responseBody = EntityUtils.toString(response.getEntity());
                System.out.print(responseBody);
            } catch(Exception e) {
                System.out.println(e.toString());
            }
        }
    };
    searchThread.run();
}

我用于测试 cookie 的 PHP 代码:

<?php
$cookies = $_COOKIE;

if(!count($cookies) > 0)
    echo 'No cookies!';

foreach ($cookies as $key=>$val)
    echo "$key--> $val";

?>

使用此代码检索 GUID:

    public void login(String usr, String pass) {
    logout();
    final String username = usr;
    final String password = pass;
    Thread loginThread = new Thread() {
        public void run() {
            try {
                DefaultHttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost("http://login.vk.com/?act=login&email=" + URLEncoder.encode(username, HTTP.UTF_8) + "&pass=" + URLEncoder.encode(password, HTTP.UTF_8));
                httpClient.execute(httpPost);
                List<Cookie> cookies = httpClient.getCookieStore().getCookies();
                for(Cookie cookie : cookies) {
                    System.out.println("Cookie: " + cookie.toString());
                    if(cookie.getName().contains("remixsid"))
                        guid = cookie.getValue();
                }
            } catch(Exception e) {
                System.out.println(e.toString());
                System.out.println("An error occured");
                if(loginHandler != null)
                    loginHandler.onLoginError(e);
                return;
            }
            if(!isLoggedIn()) {
                System.out.println("User credentials invalid");
                if(loginHandler != null)
                    loginHandler.onLoginInvalidCredentials();
                return;
            }
            if(loginHandler != null)
                loginHandler.onLoginSuccess();
            System.out.println("Login successfull GUID is: " + guid);
        }
    };
    loginThread.start();
}

Answer 1

手动设置 cookie header 似乎可行...

    public void search(String q, int o) {
    final String query = q;
    final int offset = o;
    Thread searchThread = new Thread() {
        public void run() {
            try {
                DefaultHttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost("http://192.168.1.43/test/test.php");
                //HttpPost httpPost = new HttpPost("http://vkontakte.ru/gsearch.php?section=audio&q=" + URLEncoder.encode(query, HTTP.UTF_8) + "&offset=" + offset);
                httpPost.setHeader("Cookie", "remixsid=" + guid);
                HttpResponse response = httpClient.execute(httpPost);
                String responseBody = EntityUtils.toString(response.getEntity());
                System.out.println(responseBody);
            } catch(Exception e) {
                System.out.println(e.toString());
            }
        }
    };
    searchThread.start();
}