android - 如何更改弹出菜单弹出的位置

Question

我在每个项目的 ListView 适配器中都有一个弹出菜单。菜单在屏幕的左边缘弹出，如何将其更改为在右侧

private void showPopupMenu(View v, final App app) {
    PopupMenu popupMenu = new PopupMenu(context, v);

    popupMenu.getMenuInflater().inflate(R.menu.quick_action_menu,
            popupMenu.getMenu());
    popupMenu
            .setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
                @Override
                public boolean onMenuItemClick(MenuItem item) {
                    switch (item.getItemId()) {
                    ...

Answer 1

迟到总比一次好 =) 这是我的决定，允许您将 PopupMenu 设置到指定的坐标。代码不是很好，但是可以用。

public void show(Activity activity, float x, float y)
{
    final ViewGroup root = (ViewGroup) activity.getWindow().getDecorView().findViewById(android.R.id.content);

    final View view = new View(context);
    view.setLayoutParams(new ViewGroup.LayoutParams(1, 1));
    view.setBackgroundColor(Color.TRANSPARENT);

    root.addView(view);

    view.setX(x);
    view.setY(y);

    PopupMenu popupMenu = new PopupMenu(context, view, Gravity.CENTER);

    popupMenu.setOnDismissListener(new PopupMenu.OnDismissListener()
    {
        @Override
        public void onDismiss(PopupMenu menu)
        {
            root.removeView(view);
        }
    });

    popupMenu.show();
}