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java - 严格模式提示资源泄漏

转载 作者:塔克拉玛干 更新时间:2023-11-02 23:59:38 25 4
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严格模式提示如下:在附加的堆栈跟踪中获取了资源但从未释放。有关避免资源泄漏的信息,请参阅 java.io.Closeable。:

**response = httpclient.execute(httpPost);**

下面是我的代码:

    HttpClient httpclient = new DefaultHttpClient();

String url = "example";
HttpPost httpPost = new HttpPost(url);

HttpResponse response;
String responseString = "";
try {
httpPost.setHeader("Content-Type", "application/json");

**response = httpclient.execute(httpPost);**

StatusLine statusLine = response.getStatusLine();
if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
out.close();
responseString = out.toString();
} else {
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}

return responseString;

提前致谢。

最佳答案

自 4.3 起,kenota 指出的方法已弃用。

您现在应该使用 CloseableHttpClient 而不是 HttpClient,如下所示:

    CloseableHttpClient client= HttpClientBuilder.create().build();

然后您可以使用以下方法关闭它:

    client.close();

关于java - 严格模式提示资源泄漏,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13600504/

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