c++ - 您可以覆盖基类中定义的私有(private)函数吗？

Question

我相信，派生类只能覆盖它从基类继承的那些函数。我的理解对吗？

也就是说，如果基类有一个公共(public)成员函数func，那么派生类可以覆盖成员函数func。

但是如果基类有一个私有(private)成员函数foo，那么派生类就不能覆盖成员函数foo。

我说的对吗？

编辑

在研究了 SO 成员给出的答案后，我想出了一个代码示例。我提到了我在代码中作为注释研究的要点。希望我是对的。谢谢

/* Points to ponder:
   1. Irrespective of the access specifier, the member functions can be override in base class.
      But we cannot directly access the overriden function. It has to be invoked using a public
      member function of base class.
   2. A base class pointer holding the derived class obj's address can access only those members which
      the derived class inherited from the base class. */

#include <iostream>

using namespace std;


class base
{
   private:
      virtual void do_op()
      {
         cout << "This is do_op() in base which is pvt\n";
      }

   public:
      void op()
      {
         do_op();
      }
};

class derived: public base
{
   public:
      void do_op()
      {
         cout << "This is do_op() in derived class\n";
      }
};

int main()
{
   base *bptr;
   derived d;

   bptr = &d;
   bptr->op(); /* Invoking the overriden do_op() of derived class through the public 
               function op() of base class */ 
   //bptr->do_op(); /* Error. bptr trying to access a member function which derived class 
                    did not inherit from base class */            

   return 0;
}

Answer 1

无论访问说明符如何，您都可以覆盖函数。这也是 non-virtual interface 的核心成语。唯一的要求当然是它们是虚拟的。