gpt4 book ai didi

java - android - httpsurlconnection 'get' 405 - 方法不允许

转载 作者:塔克拉玛干 更新时间:2023-11-02 23:52:43 25 4
gpt4 key购买 nike

我在 HttpsUrlConnection 上使用“获取”方法。当我在 eclipse (Windows) 上测试我的代码时,它工作正常。当我将它压缩到一个 jar 文件并在 android studio 上使用它时,它会给我“405 - 方法不允许”。什么意思,我正在运行带有错误动词的方法(预期 GET)。

这是我设置 http 方法类型的方式:

        conn.setRequestMethod("GET");

我将 http 方法设置为“get”,当我调试它时 - conn.getRequestMethod = GET 和 conn.delegate.getRequestMethod = POST。

错误响应是 - {"Message":"The requested resource does not support http method 'POST'."

delegate method type

main conn method type

已编辑 - 添加代码:

 public static HttpsURLConnection getClient(URL url, LoginToken securityToken, RequestMethod methodType, String requestFormat, String responseFormat) throws IOException, SecurityTokenException {
HttpsURLConnection conn = (HttpsURLConnection)url.openConnection();
conn.addRequestProperty("Accept-Charset", "UTF-8");
conn.addRequestProperty("Content-Type", requestFormat);
conn.addRequestProperty("Accept", responseFormat);
conn.addRequestProperty("User-Agent", "***SDK/1.0");
conn.setRequestProperty("Cache-Control", "no-cache");
if(securityToken != null) {
LoginToken.ValidateToken(securityToken);
conn.addRequestProperty("Authorization", String.format("Bearer %1$s", new Object[]{securityToken.getTemporarySecurityCode()}));
}

conn.setRequestMethod(methodType.toString());
conn.setUseCaches(false);
conn.setDoOutput(true);
return conn;
}

public Boolean IsCompleted() throws SecurityTokenException, CommandFailedException {
LoginToken.ValidateToken(this.getSecurityToken());
HttpsURLConnection conn = null;
Gson gson = (new GsonBuilder()).create();

String json;
try {
URL url = new URL(String.format("https://api.***.com/%1$s/detector/%2$s/status", new Object[]{"v1", this.getPID()}));
conn = ***Client.getClient(url, this.getSecurityToken(), RequestMethod.GET, "application/json", "text/plain");
Throwable response1;
BufferedInputStream inputStream;
if(conn.getResponseCode() != 200) {
response1 = null;
inputStream = null;

String response2;
try {
BufferedInputStream inputStream1 = new BufferedInputStream(conn.getErrorStream());

try {
response2 = HttpURLConnectionHelper.convertStreamToString(inputStream1);
} finally {
if(inputStream1 != null) {
inputStream1.close();
}

}
} catch (Throwable var41) {
if(response1 == null) {
response1 = var41;
} else if(response1 != var41) {
response1.addSuppressed(var41);
}

throw response1;
}

BadLoginResponse response4 = (BadLoginResponse)gson.fromJson(response2, BadLoginResponse.class);
if(response4 == null) {
throw new RuntimeException("Unable to process server response.");
}

throw new CommandFailedException(response4.getMessage(), conn.getResponseCode());
}

Throwable response = null;
response1 = null;

try {
inputStream = new BufferedInputStream(conn.getInputStream());

try {
json = HttpURLConnectionHelper.convertStreamToString(inputStream);
} finally {
if(inputStream != null) {
inputStream.close();
}

}
} catch (Throwable var43) {
if(response == null) {
response = var43;
} else if(response != var43) {
response.addSuppressed(var43);
}

throw response;
}
} catch (IOException var44) {
throw new RuntimeException(var44.getMessage());
} finally {
if(conn != null) {
conn.disconnect();
}

}

我该如何解决?

最佳答案

谢谢 BNK!解决方案是删除 conn.setDoOutput(true)

关于java - android - httpsurlconnection 'get' 405 - 方法不允许,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33451431/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com