linux - 在 linux 中打印某一行或 nslookup 的选项

Question

我是 linux 和 bash 的新手。我正在尝试为 IP 地址查找域名。当我使用 nslookup 时，我有一堆这样的行

nslookup 204.228.150.3 

输出

Server: 198.60.22.2
Address: 198.60.22.2#53

Non-authoritative answer:
3.150.228.204.in-addr.arpa name = www.computerhope.com.

Authoritative answers can be found from:
150.228.204.in-addr.arpa nameserver = ns.xmission.com.
150.228.204.in-addr.arpa nameserver = ns1.xmission.com.
150.228.204.in-addr.arpa nameserver = ns2.xmission.com.
ns.xmission.com Internet address = 166.70.254.2
ns1.xmission.com Internet address = 204.228.159.2
ns2.xmission.com Internet address = 207.135.133.2 

我只想在第二行打印 www.computerhope.com。我该怎么做呢？我也尝试使用主机命令。它看起来更干净。

206.153.126.75.in-addr.arpa domain name pointer www.cyberciti.biz.

如何在使用主机命令时只打印 www.cyberciti.biz？请帮忙

Answer 1

$ host 75.126.153.202 |sed -e 's/.* //'
www.cyberciti.biz.