linux - 试图了解二进制文件 (NASM) 输出的大小

Question

我有这两个文件 myboot.asm 和 theirboot.asm(分别列出):

;----------------------------------------------------------------------
; A Simple boot program that prints the string 'Hello World'
; Author: Matthew Hoggan 2012
;----------------------------------------------------------------------
Output db 'Hello',0x00            ; Output string for bios

org 0x7c00                              ; This is where BIOS loads the bootloader

entry:                                  ; Label to Signify entry to program
    jmp short begin                     ; Jump over the DOS boot record data

; --------------------------------------------
;  Boot program code begins here
; --------------------------------------------
begin:                                  ; Label to Signify entry to program
mov si, Output                          ; Get pointer to string
loop:                                   ; Top of loop to iterate over string
    mov al, [si]                        ; Move contents of pointer to al
    or al, al                           ; Check if character pointed to is Zero
    jz hang                             ; Zero signifies end of string
    call print_char                     ; Print current char in al
    jmp loop                            ; Repeat

; --------------------------------------------
; Function to print char
; assume caller has placed char in al
; --------------------------------------------
print_char:
    mov ah, 0x0e                        ; Function to print a character to the screen
    mov bl, 7                           ; color/style to use for the character
    int 0x10                            ; print the character

hang:
        jmp     hang                    ; just loop forever.

;---------------------------------------------
; Write Zeros up to end of program - 2 then boot signature
;---------------------------------------------
size    equ     $ - entry
        times   (512 - size - 2) db 0
        db      0x55, 0xAA              ;2  byte boot signature

---

;----------------------------------------------------------------------
; A Simple boot program that prints the string 'Hello World'
;----------------------------------------------------------------------
org 0x7c00                              ; This is where BIOS loads the bootloader

entry:                                  ; Label to Signify entry to program
    jmp short begin                     ; Jump over the DOS boot record data
; --------------------------------------------
;  Boot program code begins here
; --------------------------------------------
begin:                                  ; Label to Signify entry to program
    xor ax, ax                          ; Zero out ax
    mov ds, ax                          ; Set data segment to base of RAM
    mov si, msg                         ; Get pointer to string
    call putstr                         ; Print the message
    jmp hang                            ; Go to infinite loop

msg db 'Hello, World',0x00

putstr:                                 ; Function to print the string
    lodsb                               ; al = [DS:SI]
    or al, al                           ; Set zero flag if al = 0
    jz ret                              ; Jump to end of function if al = 0
    mov ah, 0x0e                        ; Video function 0Eh (print char)
    mov bx, 0x0007                      ; Color
    int 0x10
    jmp putstr
ret:
    retn

hang:
        jmp     hang                    ; just loop forever.

;---------------------------------------------
; Write Zeros up to end of program - 2 then boot signature
;---------------------------------------------
size    equ     $ - entry
        times   (512 - size - 2) db 0
        db      0x55, 0xAA              ;2  byte boot signature

构建这两个文件并在其上运行 hexdump 并列出目录中的文件以查看它们的大小显示:

mehoggan@mehoggan-laptop:~/Code/play/asm$ nasm myboot.asm -f bin -o boot.bin && hexdump boot.bin && ls -l && echo "------" && nasm bootloader1.asm -f bin -o boot.bin && hexdump boot.bin && ls -l
0000000 6548 6c6c 006f 00eb 00be 8a7c 0804 74c0
0000010 e80c 0003 f4e9 b4ff b30e cd07 e910 fffd
0000020 0000 0000 0000 0000 0000 0000 0000 0000
*
0000200 0000 0000 aa55                         
0000206
total 20
-rw-r--r-- 1 mehoggan mehoggan  518 2012-02-29 21:57 boot.bin
-rw-r--r-- 1 mehoggan mehoggan 2290 2012-02-29 20:23 bootloader0.asm
-rw-r--r-- 1 mehoggan mehoggan 1661 2012-02-29 21:55 bootloader1.asm
-rw-r--r-- 1 mehoggan mehoggan 1786 2012-02-29 21:49 myboot.asm
-rw-r--r-- 1 mehoggan mehoggan 1065 2012-02-29 20:14 ourbootloader.asm
------
0000000 00eb c031 d88e 0fbe e87c 0010 1de9 4800
0000010 6c65 6f6c 202c 6f57 6c72 0064 08ac 74c0
0000020 b40a bb0e 0007 10cd f1e9 c3ff fde9 00ff
0000030 0000 0000 0000 0000 0000 0000 0000 0000
*
00001f0 0000 0000 0000 0000 0000 0000 0000 aa55
0000200
total 20
-rw-r--r-- 1 mehoggan mehoggan  512 2012-02-29 21:57 boot.bin
-rw-r--r-- 1 mehoggan mehoggan 2290 2012-02-29 20:23 bootloader0.asm
-rw-r--r-- 1 mehoggan mehoggan 1661 2012-02-29 21:55 bootloader1.asm
-rw-r--r-- 1 mehoggan mehoggan 1786 2012-02-29 21:49 myboot.asm
-rw-r--r-- 1 mehoggan mehoggan 1065 2012-02-29 20:14 ourbootloader.asm

为什么文件大小减少了 6 个字节？

Answer 1

检查最后一小块汇编代码:

size    equ     $ - entry
        times   (512 - size - 2) db 0
        db      0x55, 0xAA              ;2  byte boot signature

此代码块计算代码有多大(从 entry 到当前位置)，然后用零和签名 0x55 0xAA< 将其填充到总共 512 个字节 在最后两个位置。即:

entry: Some code
       .
       .
       .
  Some zeroes
       .
       .
       .
   0x55 0xAA 

那个小汇编 block 意味着从 entry 标签到 0x55 0xAA 的输出大小总是 512 字节。在您的第一个示例中，entry 之前有一个六字节字符串 Hello\0。在你的第二个例子中没有。因此，第一个程序比第二个程序长六个字节。您可能希望将该字符串移动到 entry 之后和填充 block 之前的某个位置。

如果您对二进制文件使用 hexump -C，您会在第一个二进制文件的顶部看到该字符串。