c++ - Phong 着色器中不需要的透明度 - GLSL

Question

我正在尝试创建一个基本的 Phong 照明着色器以了解着色器中的照明。另外，我正在使用 openframeworks。我创建了 3 个立方体，它们有一个围绕它们旋转的相机。照明似乎正常工作(有点)，但立方体具有不需要的透明度，您可以在此处看到:

这是我的代码，它基于 this tutorial

测试应用.h

#pragma once

#include "ofMain.h"

class testApp : public ofBaseApp{

public:

ofCamera camera;
ofLight pointLight;
float camAngle;
float camX;
float camY;
float camZ;

ofShader lightShader;

ofBoxPrimitive box1;
ofBoxPrimitive box2;
ofBoxPrimitive box3;

void setup();
void update();
void draw();
};

测试应用.cpp

#include "testApp.h"

//--------------------------------------------------------------
void testApp::setup()
{
glEnable(GL_DEPTH_TEST);
glEnable(GL_LIGHTING);

ofBackground(100, 100, 100);
ofSetFrameRate(30);

camera.setNearClip(0.1);
camera.setFarClip(1200);
camAngle = 0;
camX = 200;
camY = 150;
camZ = 200;

pointLight.setPointLight();

lightShader.load("shaders/lightShader");

//boxes setup here, not necessary to show

}

//--------------------------------------------------------------
void testApp::update()
{
camAngle += 0.01f;

if (camAngle >= 360)
{
    camAngle = 0;
}

camX = 300 * sin(camAngle);
camZ = 300 * cos(camAngle);


camera.lookAt(ofVec3f(0, 0, 0));
camera.setPosition(ofVec3f(camX, camY, camZ));

pointLight.setPosition(-50, -20, 200);
}

//--------------------------------------------------------------
void testApp::draw()
{
lightShader.begin();
    camera.begin();
    pointLight.enable();
        pointLight.draw();
        ofVec3f lightLocation = pointLight.getPosition();
        lightShader.setUniform3f("lightLocation", lightLocation.x, lightLocation.y, lightLocation.z);
        box1.draw();
        ofPushMatrix();
        ofTranslate(60, 50);
        ofRotate(45, 1.0, 0.0, 0.0);
        box2.draw();
        ofPopMatrix();
        ofPushMatrix();
        ofTranslate(-70,70);
        ofRotate(110, 1.0, 0.0, 0.6);
        box3.draw();
        ofPopMatrix();
    pointLight.disable();
    camera.end();
lightShader.end();
}

lightShader.vert

// vertex shader

#version 150

//these are passed in by openframeworks
uniform mat4 modelViewProjectionMatrix;
in vec4 position;
in vec4 color;
in vec3 normal;
in vec2 texcoord;

out vec4 vertPosition;
out vec4 vertColor;
out vec3 vertNormal;
out vec2 texCoordVar;

void main()
{
texCoordVar = texcoord;
vertPosition = position;
vertColor = color;
vertNormal = normal;
gl_Position = modelViewProjectionMatrix * position;
}

lightShader.frag

// fragment shader

#version 150

uniform mat4 modelViewMatrix;
uniform mat4 modelViewProjectionMatrix;
uniform vec3 lightLocation;
uniform vec3 lightIntensity;

in vec2 texCoordVar;
in vec3 vertNormal;
in vec4 vertPosition;
in vec4 vertColor;

out vec4 outputColor;

void main()
{
//calculate normal in world coordinates
mat3 normalMatrix = transpose(inverse(mat3(modelViewMatrix)));
vec3 vertexNormal = normalize(normalMatrix * vertNormal);

//calculate the location of this pixel in world coordinates
vec3 fragPosition = vec3(modelViewMatrix * vertPosition);

//calculate the vector from this pixels surface to the light source
vec3 surfaceToLight = normalize(lightLocation - fragPosition);

//calculate the cosine of the angle of incidence (brightness)
float brightness = max(0.0, dot(vertexNormal, surfaceToLight));

//calculate final color of the pixel
outputColor = brightness * vec4(vertColor.rgb, 1.0);
}

通过一些实验，我发现如果我将片段着色器的最后一行更改为:

outputColor = brightness * (vec4(vertColor.rgb, 1.0) * modelViewProjectionMatrix);

我明白了:

颜色不对，灯光变得很黑，但物体本应是不透明的。所以，也许我应该以某种方式使用 modelViewProjectionMatrix？不确定如何。

Answer 1

将亮度乘以 alpha channel :

outputColor = brightness * vec4(vertColor.rgb, 1.0);

你可以这样做:

outputColor = brightness * vec4(vertColor.rgb, 1.0);

然后:

outputColor.a = 1.0;

不，您不必以这种方式使用 modelViewProjectionMatrix:

outputColor = brightness*(vec4(vertColor.rgb, 1.0) * modelViewProjectionMatrix);

您只需要modelViewProjectionMatrix 获取顶点的屏幕空间坐标